Take multiple inputs in a single line.

[kunalgaurav18]

I want to take input in the following way:
Sample Input 1
3
45 3 14

Sample Input 2
5
12 34 5 56 7

The first line is the number of test cases and the second line is the corresponding values for the test cases.
Please give me the java code for taking multiple inputs in the single line separated by a space.

[Toll]

Have a look at String.split().

[kunalgaurav18]

Have a look at String.split().

Will you please make it some clear with the help of some codes it is not becoming clear for me from your given link.

[sjicho]

try

import java.util.Scanner;

public class Random {
public static void main(String args[]) {
Scanner scanner = new Scanner(System.in);
System.out.print("Number of integers: ");
int intNumberOfIntegers = scanner.nextInt();

int intStorage[] = new int[intNumberOfIntegers];

System.out.println("Please prompt numbers!");

for(int i = 0;i < intStorage.length;i++) {
intStorage[i] = scanner.nextInt();
}

System.out.println("Your numbers are");

for(int i = 0;i < intStorage.length;i++) {
System.out.print(intStorage[i] + " ");
}
}
}

[kunalgaurav18]

try

import java.util.Scanner;

public class Random {
public static void main(String args[]) {
Scanner scanner = new Scanner(System.in);
System.out.print("Number of integers: ");
int intNumberOfIntegers = scanner.nextInt();

int intStorage[] = new int[intNumberOfIntegers];

System.out.println("Please prompt numbers!");

for(int i = 0;i < intStorage.length;i++) {
intStorage[i] = scanner.nextInt();
}

System.out.println("Your numbers are");

for(int i = 0;i < intStorage.length;i++) {
System.out.print(intStorage[i] + " ");
}
}
}

Thanks!! It works

[DarrylBurke]

try

import java.util.Scanner;

public class Random {
public static void main(String args[]) {
Scanner scanner = new Scanner(System.in);
System.out.print("Number of integers: ");
int intNumberOfIntegers = scanner.nextInt();

int intStorage[] = new int[intNumberOfIntegers];

System.out.println("Please prompt numbers!");

for(int i = 0;i < intStorage.length;i++) {
intStorage[i] = scanner.nextInt();
}

System.out.println("Your numbers are");

for(int i = 0;i < intStorage.length;i++) {
System.out.print(intStorage[i] + " ");
}
}
}

1. Don't spoonfeed. With the guidance already given, the OP could have figured out the code -- or asked for clarification. A forum is a place to learn, not a free code handout center.

2. Go through Guide For New Members and BB Code List - Java Programming Forum and edit your post accordingly.

3. It's bad practise (a) to name a class after an existing JDK class and (b) to use a meaningless class name that doesn't reflect its purpose.

db

[sjicho]

Sorry for that it won't happen again I am also new to this forum but I do acknowledge my mistakes

[traisjames]

When you look at String.split(), one thing it says is the call [CODE]public String[] split(String regex)[/CODE
Other important infomation is

Splits this string around matches of the given regular expression.
This method works as if by invoking the two-argument split method with the given expression and a limit argument of zero. Trailing empty strings are therefore not included in the resulting array.

The string "boo:and:foo", for example, yields the following results with these expressions:

Regex Result
: { "boo", "and", "foo" }
o { "b", "", ":and:f" }
Parameters:
regex - the delimiting regular expression
Returns:
the array of strings computed by splitting this string around matches of the given regular expression

So what happens in the example given is:

String mystring;
String[] myarray = new String[3];

mystring = "boo:and:foo";
myarray = mystring.split(':');

which could also be

String mystring;
int[] myarray = new int[3];

mystring = "50 20 3";
myarray = mystring.split(' ');

For both of these, lines 1 and 2 define the variables we are going to work with, line two is the array which the string will be seperated and stored into.
Line 3 is the data we are going to work with. This data can come in via some file or user entered data. : or a space is what seperates the parts of data.
Line 4 does the work of splitting the data based on the character listed in the (). The output is an array where each element is what is between the separator. This is what the Returns line in the description sheet says.

[DarrylBurke]

...
which could also be

String mystring;
int[] myarray = new int[3];

mystring = "50 20 3";
myarray = mystring.split(' ');

No, it couldn't also be.

I suggest you test any code before posting.

db

[traisjames]

No, it couldn't also be.

I suggest you test any code before posting.

db

your right it should be

String[] myarray = new String[3];
String mystring;
mystring = "50 20 3";
myarray = mystring.split(" ");

I wrote it quick as an example.

[DarrylBurke]

your right it should be

String[] myarray = new String[3];

No, it shouldn't be. Read the requirement:

The first line is the number of test cases ...

db

[traisjames]

I know. again it was a demo to show the spit function

[DarrylBurke]

it was a demo to show the spit function

Java has methods. Not functions.

You may think I'm being nitpick-ety, but written communication on a forum, unlike verbal communication whether face-to-face or via telecom, can't be instantly clarified when there's a slight misunderstanding. Because of that, it is necessary to be precise. Anything less could mislead the reader.

Have you seen the documentation for String#split(...)? There's an example provided there, which should be adequate for someone learning how to use the method.

db

[traisjames]

I did which is what I mentioned in my first post. I think they could be a little bit clearer...maybe runable examples. sometimes they can be confusing to read.