Help needed for Diving Program

[v1ru5]

Hey guys,

I need some help on this assignment Question 4/5:

http://www.site.uottawa.ca/~mseha092...2_Fall2012.pdf

So basically this is what I have done:

// This is a template to be used for all single-class ITI 1120 programs.

/**
 * Replace this comment with a description of your program.
 */

import java.util.Scanner;

class A2Q5 // Replace 'Template' with your own algorithm name.
{
  public static void main (String args[ ])
  {
    // DECLARE VARIABLES/DATA DICTIONARY
    Scanner keyboard = new Scanner (System.in);
    int tMax = 0;
    String diveAgain = "y";
    
    while (true)
    {
      if (!diveAgain.equals("y"))
      {
        break;
      }
    // READ IN GIVENS use our ITI1120 special class for keyboard input    
    System.out.print ("Please enter the maximum time in seconds to make a dive: ");
    tMax = keyboard.nextInt();
    dive (tMax);
    System.out.println ();
    System.out.println ();
    System.out.print ("Do you wish to make another dive attempt?(y/n): ");
    diveAgain = keyboard.nextLine();
    
    // BODY OF ALGORITHM - Call to the method to solve problem
    // PRINT OUT RESULTS AND MODIFIEDS
    }
  }
  
  // Problem Solving Method
  // Description: Short description of what the
  // method does, 
  // Parameters (GIVENS): 
  //    A description of variables in the parameter list
  public static void dive(int tMax)
  {  
    // DECLARE VARIABLES/DATA DICTIONARY
    // INTERMEDIATES8
    
    double probability = 0;
    double distance = 0;
    
    double randomNum = 0;
    // RESULT
    char[] moves = new char[tMax];
    
    // BODY OF ALGORITHM
    for (int i = 0; i<(moves.length-1); i++)
    {
    randomNum = 0 + Math.random();
    System.out.println (randomNum);
    probability = 1 - (distance/10);
    System.out.println (probability);
    if (randomNum < probability)
    {
      moves[i] = ('F');
      distance+=2;
    }
    else
    {
      moves[i] = ('B');
      distance--;
    }
    }
    if (distance >= 10)
    {
      moves[moves.length-1] = ('D');
      System.out.print ("The man jumped with the moves ");
      for (int i = 0; i <= moves.length-1; i++)
      {
        System.out.print (moves[i]);
      }
      System.out.print (" in " + (moves.length-1) + " seconds");
    }
    else
    {
      System.out.print ("The man lost his nerve after the moves ");
      for (int i = 0; i <= moves.length-1; i++)
      {
        System.out.print (moves[i]);
      }
    }
         
  }
  
} // Don't remove this brace bracket!

For some reason, the person never jumps. Basically since each step forward is two steps and each step backward is one step, after the difference between the two the guy needs to have 10 steps forward in order to jump off but that never happens. If anyone knows what I am doing wrong, any help would be appreciated.

Thanks!

[arieltal]

when i ran your code, the man did jump on some occasions, i guess it's just the random numbers,

[v1ru5]

when i ran your code, the man did jump on some occasions, i guess it's just the random numbers,

Still not getting the man to jump. I think I know what the problem is though. I need to make the for loop exit when distance equals 10 because even when distance equals 10 it still continues and so the man moves backwards. So my question was, how can I make a for loop exit:

if (randomNum < probability)
    {
      moves[i] = ('F');
      distance+=2;
      if (distance == 10)
      {
         What would I put here to exit for loop?
      }  
    }
    else
    {
      moves[i] = ('B');
      distance--;
    }

[v1ru5]

Nvm, I added a break and it works. But now I am getting an output that looks like this:

The man jumped with the moves FFFFBFBF(16 blank spaces)D in 24 seconds.

How am I supposed to get rid of the blank spaces in the array since the arrays size is the size of the maximum time.

[arieltal]

you can add 'D' at the moment he jumps and ignore the rest of the array

[v1ru5]

okay, but how do I ignore the rest of the array?

[Toll]

You can use "break" to stop a for-loop (or a while-loop) from running.