Java, Random and ?

[rldme]

Can you tell me what the "?" mark is in this code (i.e. what its called)

Random rand = new Random();
int choice = (rand.nextInt(100)<75) ? 1:0;

When the code is run it returns either 1 or 0.
It returns 1 75% of the time.
I have played with the 1:0 values if you change it to 5:10 for example it returns the number 5, 75% of the time.
I want to understand what the ? is doing. I get that it some how identifies that of the two values it returns the first one 75% more than the second one.
And if you change the 75 to 25 it would then return the first value (1) 25% of the time vs. second value.
But I can't find any documentation on the ? or what other options I could use in place of it.

Thanks

[penguinCoder]

The question mark is just a different form of the if statement. The following two snippets of code do exactly the same things:

public Foo generateFoo(int threshold)
{
    if(threshold > MIN_THRESHOLD)
       return new Foo();
    else
       return null;
}

public Foo generateFoo(in threshold)
{
    return (threshold > MIN_THRESHOLD) ? new Foo() : null;
}

[rldme]

Thank you now I remember that aspect. Have a great day.

[DarrylBurke]

It's called a ternary expression.

The question mark is just a different form of the if statement.

Not really, no. The ternary expression is a value expression which must evaluate to a valid value.

This won't compile, because void isn't a valid value:

... {
  boolean condn = false; // or true
  condn ? setInt(0) : setInt(1);
}

void setInt(int value) {
  ...
}

db