# Random 1-10 guessing game with 3 tries

• 10-01-2012, 04:25 PM
sethe23
Random 1-10 guessing game with 3 tries
Hi guys,

I've got some what of an easy problem I would guess, I just think that I have my function in the wrong place. This is an assignment in class that I have had much issues with trying to get it to break out of a while loop using boolean variables (because break is bad coding practice). Anyways, I've tried using regular int boolean such as
Code:

```int test = 0; ... while (test ==0) {... } test = 1;```
and I have not had much luck. If you could help it would be great! Thanks, -Seth
• 10-01-2012, 04:29 PM
PhQ
Re: Random 1-10 guessing game with 3 tries
To break out the while loop your 'test ==0' needs to become true at some point in the while loop. The while loop will not do anything as it is true to begin with. Because the variable test is 0 to start off with.
• 10-01-2012, 04:31 PM
sethe23
Re: Random 1-10 guessing game with 3 tries
I posted the code separately to be easier to read: I did not include the header so you can run this on an open program.
Code:

```boolean quit = false;         int i = 0;       while (quit == false) {             Random seed = new Random();             int answer = seed.nextInt(10);             System.out.println(answer);//remove later             Scanner input = new Scanner(System.in);                         int guess = input.nextInt();             if (guess > answer) {                 System.out.println("Your guess is too high \n");             } else if (guess < answer) {                 System.out.println("Your answer is too low \n");             }                                   //*************************************************             while (guess != answer) {                   i++;                   if (i==3){                 quit = true;                 System.out.println("Test");             }                           System.out.println("this is i:" + i);                 int retry = input.nextInt();                 if (retry > answer) {                     System.out.println("Your guess is too high \n");                 } else if (retry < answer) {                     System.out.println("Your answer is too low \n");                 }                 if (retry == answer) {                     guess = answer;                 }             }              System.out.println("You win!");       }         System.out.println("Sorry you lose :(");       }     }```
• 10-01-2012, 04:39 PM
sethe23
Re: Random 1-10 guessing game with 3 tries
Well for my instance, would it be possible to convert it to true by using if statements and counters?
Code:

```boolean test = false; int i = 0; while (test ==false) { i++; ... if (i =3) { test = true }```
• 10-01-2012, 04:45 PM
PhQ
Re: Random 1-10 guessing game with 3 tries
This will not stop your main loop:
Code:

```if (i == 3) {                                         quit = true;                                         System.out.println("Test");                                 }```
as it is stuck in the while (guess != answer) { loop.
You need to break out of this loop:
before breaking out of this: while (quit == false) {.
• 10-01-2012, 04:46 PM
PhQ
Re: Random 1-10 guessing game with 3 tries
Quote:

Originally Posted by sethe23
Well for my instance, would it be possible to convert it to true by using if statements and counters?
Code:

```boolean test = false; int i = 0; while (test ==false) { i++; ... if (i =3) { test = true }```

Yea, you can do something like this.
• 10-01-2012, 04:53 PM
sethe23
Re: Random 1-10 guessing game with 3 tries
I figured it was something simple like placement. I am not exactly sure how I could break out of the whole while (guess!=answer) entirely. I thought by making it equal true in the program would break the statement.