Command line argument

**denisatandi** · 02-18-2008, 12:18 PM

I'm new to Java, can someone please tell me how you can use a command line argument to print a message several times? Say if you wanted to print Hello world three times and you have to enter 3 for the message to print three times.
Thank you

**Eranga** · 03-03-2008, 06:39 AM

In Java command-line arguments are passes to the application main method using an array of strings.

Java Code:

public static void main (String[] arguments)
{
// Body of the main method.
}

If you want to use a numeric value, you have to get it from a string array. Something like this,

Java Code:

int numericValue = Integer.parseInt(arguments[0]);

this line of code gives a numeric value. So in your application you can do this.

Java Code:

class Test
{
public static void main(String[] arguments)
{
int numberOfTurns = Integer.parseInt(arguments[0]);
while(0 < numberOfTurns)
{
System.out.println("Hello World");
numberOfTurns--;
}
}
}

**ferranb** · 06-14-2008, 03:23 AM

Notice that in java the argument 0 is not the executable like others languages like C/C++.

Ferran

**Eranga** · 06-15-2008, 06:59 AM

I'm not clear what you are talking about. In my explanation, I'm not talking about anything related to executable commands. Basically over friend felt difficult with how to handle command line arguments in Java. May be the following code snippets can be helped. But I don't want to send this earlier because there is no response from thread starter. :)

Java Code:

class Test {
	public static void main(String[] arguments) {
		else if(arguments.length == 2){
			String text = arguments[0];
			int terms = Integer.parseInt(arguments[1]);
			for(int i = 0; i < terms; i++) {
				System.out.println(text);
			}
		}
		else {
			System.out.println("Invalid");
		}
	}
}

Here you need two command parameters to run the code.

**niloufar** · 10-16-2012, 05:39 AM

Hi, I'm using Comment arguments and can't pass those values into my validatation method and not sure were to parse my string args to int. can you check my code and let me know what i'm doing wrong Pleaaaaaaaaase? Thank you

Java Code:

public class test {
	
	// Global Constants
    final static int MIN_NUMBER = 1;
    final static int MAX_PRIME = 10000;
    final static int MAX_FACTORIAL = 12;
    final static int MAX_LEAPYEAR = 4000;
  
    //Global Variable
    static int a,b,c;
	
	
public static void main (String[] args) {
		String[] myNumbers= new String [3];
				
		for(int i =0; i< args.length; i++){
			//System.out.print(args[i]+" ");
			validateInput(myNumbers);
			
		
		}
		
	}
			
					
//Validate User Input
	public static boolean validateInput(String[] array){
		String[] arrayCopy = copyArray(array);
		boolean isValid = false;
				
		try {
			
			for(int i = 0; i < array.length; i++) {
			a=Integer.parseInt(arrayCopy[0]);
			if(!withinRange(array)) {
              isValid = true; 
	          System.out.println("The entered value " + array[0] + " is not a valid integer.  Please try again.");
			}
		} 
	}
			 catch(Exception ex) { 
	          
	        }
	        return isValid;
	    }
	
	
	/**
	 * Copies the array.
	 * @param array The array to copy.
	 * @return A copy of the input array.
	 */	
	private static String[] copyArray(String[] array) {
		String[] copy = new String[array.length]; // Declare an array with a size equal to the length of the input array
		
		for(int x = 0; x < copy.length; x++) {
			copy[x] = array[x]; // Assign each value of the input array to the new array
		}
		return copy; // Return the copied array
	}
	
//Check the value within the specified range
		private static boolean withinRange(String [] array) {
			String[] arrayCopy= copyArray(array);
			
	     boolean isInRange = true; 
	    
	     for(int i =0; i< arrayCopy.length; i++){
	     if(arrayCopy.length < MIN_NUMBER && arrayCopy.length > MAX_PRIME) {
	         System.out.println("The entered value "+ (arrayCopy[i]) +" is out of range [1 TO 1000].");
	         isInRange = false; 
	     }
	    
	     }
	     return isInRange;
	 }
		}
		
		
}