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Thread: Java random numbers in an array!
 09122012, 06:01 AM #1Member
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Java random numbers in an array!
I have to initialized a 6 row by 6 column array. And am trying to add ten 5's in the array. And then print it but it wont work. I tried for 2 hours cant help it, can anyone please help me!
Thank you forum!
Java Code:package HW7_5_3; import java.util.Scanner; import java.lang.Math; public class Task5review { public static void main(String[] args) { int array1[][] = new int [6][6]; int num; int count=0; if(count<10) { for(int i=0;i<6;i++) { for(int k=0;k<6;k++) { num=(int)(Math.random()*(21)+2); if (num==1&&count<10) { array1[i][k]=5; count++; } if (num==2) { array1[i][k]=0; } } } } for(int i=0;i<6;i++) { for(int k=0;k<6;k++) { System.out.print(array1[i][k]+" "); } System.out.println(""); } } }
 09122012, 06:16 AM #2Member
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Re: Java random numbers in an array!
Sorry nvm i got it thenk you for who ever looked at it this is the solution
Java Code:package HW7_5_3; import java.util.Scanner; import java.lang.Math; public class Task5review { public static void main(String[] args) { int array1[][] = new int [6][6]; int num; int count=0; if(count<10) { for(int i=0;i<6;i++) { for(int k=0;k<6;k++) { num=(int)(Math.random()*(21+1)+1); if (num==1&&count<10) { array1[i][k]=5; count++; } if (num==2) { array1[i][k]=0; } } } } for(int i=0;i<6;i++) { for(int k=0;k<6;k++) { System.out.print(array1[i][k]+" "); } System.out.println(""); } } }
 09122012, 07:04 AM #3
Re: Java random numbers in an array!
It is recommended to use appropriate methods of java.util,.Random instead of Math#random()
dbIf you're forever cleaning cobwebs, it's time to get rid of the spiders.
 09122012, 09:44 AM #4
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Re: Java random numbers in an array!
That algorithm doesn't always produce ten '5's at random positions in your two dimensional array.
kind regards,
JosI have the stamina of a seal; I lie on the beach instead of running on it.
 09132012, 06:39 AM #5Member
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 09132012, 08:25 AM #6
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