Why does adding 1 to a int var within a println method treat as if they were string?

[AcousticBruce]

Why does this...

System.out.println("Die " + i + 1 + ": " + dieArray[i]);

Add the 1 to i as if it was strings? I tried (i+1) also and still same result.

Die 01: 4
Die 11: 6
Die 21: 6
Die 31: 6
Die 41: 4

So I tried this and it worked....

System.out.printf("\nDie %d: %d", i+1, dieArray[i]);

does this....

Die 1: 4
Die 2: 5
Die 3: 2
Die 4: 1
Die 5: 6

[awinston]

I tried (i+1) also and still same result.

This code should add the integer value of i to the integer value of 1 and print that value out:

System.out.println("Die " + (i + 1) + ": " + dieArray[i]);

I think that you may have mistyped something when you tried it before. I recommend that you try it again.

[kjkrum]

Syntactic sugar - Wikipedia, the free encyclopedia

[Fubarable]

To answer your question, you need to dive into the Java Language Specification, or JLS, and in particular Section 5.4 on String conversion which states:

String conversion applies only to an operand of the binary + operator which is not a String when the other operand is a String.

In this single special case, the non-String operand to the + is converted to a String (§5.1.11) and evaluation of the + operator proceeds as specified in §15.18.1.

[AcousticBruce]

I understand fully on why it became a String. Thanks for the advice.
Awinston you were correct. I did something wrong and am not sure what but I got it.