How to check the value entered in the texbox is numeric or non numeric in java

[newbie_tiwari]

Hi all,

I am newbie in RFT aswell as in java so could u pls help me
actually i want to check for a textbox that the value we entered is numeric or non numeric as the textbox will only take the numeric value.. pls guyss help me.

[Norm]

One way would be to use the Integer class's parseInt() method in a try/catch block

[Java2012]

Another way...... please take a look at this code:

public  boolean isnum(String st)
  {
      boolean yes = true;
      
      for(int i = 0; i < st.length();i++)
      {
          if(!helpIsnum(st.charAt(i)))
          {
             yes = false;
             break;
          }
      }
      
      return yes;
  }
  
  public  boolean helpIsnum(char c)
  {
      boolean yes = false;
      
      if("0123456789.".contains("" + c))
          yes = true;
      
      
      return yes;
      
  }

[Norm]

The Character class has a method that says if a char is numeric.

[Java2012]

The Character class has a method that says if a char is numeric.

In this case, he does not need the help function.

Can you name that char class function please?

[Norm]

Take a look at the API doc. It is all documented there. The Character class has lots of useful methods.
Java Platform SE 6
http://docs.oracle.com/javase/7/docs/api/index.html

Find the class in the lower left and click on the link for the doc to be shown in the main frame.

[Java2012]

This is it:

isDigit(char ch)

Thanks

[SJF]

Well.. yearly is not a char. Character.isDigit(char c) is for one char....

This program will crash before then anyway when the percent.nextInt() fires on a string.... (nextInt() gets an int value out of stdin, not a double!)

     String str;
     // .....
     str = percent.nextLine();
     try{
		double d = Double.parseDouble(str);
	}
     catch(NumberFormatException nfe){
		System.out.println("That's not a double!");
     }

Or something similar to keep strings from blowing up your program.