Find \t \n in text

[onions]

Hi! So I have gotten a string from a JTextPane using

         int length = textPane.getDocument().getLength();
         text = textPane.getDocument().getText(0, length);

Now my problem is in tokenizing it.

If the text was
"A
sample text!
[There is a tab here]Example."

I would want the output to be:
TOKEN: A
TOKEN: \n
TOKEN: sample
TOKEN: text
TOKEN: !
TOKEN: \t
TOKEN: Example
TOKEN: .

But instead, the code can't seem to read the \n and \t and they just come out blank. (They are not equal to spaces though)
Is there a way to find these in the text?

public ArrayList tokenizeText(String text){
            ArrayList <String> sen=new ArrayList<String>();
            String word="",string="";
            char c;
            for(int i=0;i<text.length();i++){
                c=text.charAt(i);
                if(Character.isLetter(c)){
                    while(Character.isLetter(c) && i<text.length()){
                    word+=c;
                    c=' ';
                        if(i+1<text.length() && Character.isLetter(text.charAt(i+1))){
                            i++;
                            c=text.charAt(i);
                        } 
                    }
                   word=word.trim();
                   sen.add(word);
                   word="";
                }
                else if(Character.isDigit(c)){
                  while(Character.isDigit(c) && i<text.length()){
                    word+=c;
                    c=' ';
                        if(i+1<text.length() && Character.isDigit(text.charAt(i+1))){
                            i++;
                            c=text.charAt(i);
                        } 
                    }
                   word=word.trim();
                   sen.add(word);
                   word="";
                }
                else if(c==' '){
                    while(c==' ' && i<text.length()){
                        sen.add("SPACE");
                        word+=c;
                        c='z';
                        if(i+1<text.length() && text.charAt(i+1)==' '){
                            i++;
                            c=text.charAt(i);
                        } 
                    }
                }
                else if(c=='\\'){                  //This part of the loop is never entered when i test it
                    if(i+1<text.length()){
                        if(text.charAt(i+1)=='n')
                        {   i++; 
                            sen.add("NEWLINE");
                        }
                        else if(text.charAt(i+1)=='r'){
                            i++;
                            sen.add("RETURN");
                        }
                        else if(text.charAt(i+1)=='t'){
                            i++;
                            sen.add("TAB");
                        }
                    }
                    else
                        sen.add("\\");
                }
                else{
                    string=c+" ";
                    string=string.trim();
                    sen.add(string);
                }
            }
           for(int i=0;i<sen.size();i++)
                    System.out.println("TOKEN: "+sen.get(i));
            return sen;
        }

This will output:

TOKEN: A
TOKEN:
TOKEN: sample
TOKEN: SPACE
TOKEN: text
TOKEN: !
TOKEN:
TOKEN:
TOKEN: Example
TOKEN: .

[Sierra]

"else if(c=='\\'){ //This part of the loop is never entered when i test it"

Of course not, because 'c' does not contain a backslash...Not that the notation '\n' is ONE character - the backslash is used by the compiler to determine that the following character is not a normal character but a special one. You cannot check for a backslash... you need to use a switch statement:

switch(c)
{
  case '\n': // etc....
    break;
}

EDIT: My suggestion is you change line 33 to a pure 'else' statement and in that one you include the switch.

[Tolls]

Those characters are not two characters (a '\' followed by a 'n' for example). They are single characters, eg by the escaped '\n'.
So check for:

if (char[i] == '\n') ...

which would check for a tab, rather than:

if (char[i] == '\\')
    if (char[i+1] == 'n')

which would check for a '\' followed by the letter 'n'.

[Tolls]

Bah!
Slow, aged typing fingers!

[Sierra]

Don't talk about age... :)

[onions]

The switch worked perfectly. Thank you! :)