Quick 'this' question

[stuckonjava]

public class testers{
private int x =0;
public testers(int x ){
this.x = this.x +1;
x = this.x + 2;
}
public static void main(String[] args){
testers app = new testers(5);
System.out.println(app.x);


}

}

I was just wondering why this always prints 1. I'm confused with the this.x = this.x + 1 line, what does it mean?
Also in the main method what does app.x mean?

Thanks very much for your time.

[eRaaaa]

The parameter int x of your testers method covers the declared variable private int x. So if you want to use the class/object x variable, you have to use the this keyword to distinguish!
The x variable in the testers method is only visible in the body of the method and app.x shows to the private int x.
This is only 1, because this.x = this.x +1 -> 0 + 1 = 1
If you would add a System.out.println(x) in the testers method (at the end) it would print 3 -> 1(the "global x") + 2 = the local x = 3

[stuckonjava]

The parameter int x of your testers method covers the declared variable private int x. So if you want to use the class/object x variable, you have to use the this keyword to distinguish!
The x variable in the testers method is only visible in the body of the method and app.x shows to the private int x.
This is only 1, because this.x = this.x +1 -> 0 + 1 = 1
If you would add a System.out.println(x) in the testers method (at the end) it would print 3 -> 1(the "global x") + 2 = the local x = 3

How does app.x show the private int x, I thought as it was private it can't be accessed by the main.

[eRaaaa]

Why? private says that it is visible only in this/own whole class! The main method is declared in the same class, so no problem here. If you would add the main method in another class (e.g. class Starter) then you're right