how would i do this?

[carlos123]

a program using the terminal that determines the number of odd even and zero digits in an inputted value

[carlos123]

Code:

import java.util.Scanner;
public class integervaluereader
{
    public static void main (String[] args)
    {
        int place=0;
        Scanner scan = new Scanner(System.in);
        System.out.println("Enter a number..");
        String input = scan.nextLine();
        int length = input.length();
        
        
        
        //char charAt(int index)
        
        for(int f=0; f<length; f++)
        {
            char charat = input.charAt(f);
            int charvalue = parseInt(charat);//error? this is where i need help.
            
        }

        
    }
}

[CaptainMorgan]

What class is the method parseInt(char) apart of? Once you find that out, you should be able to write the correct code.

[carlos123]

there isnt a parseInt(char) method

[carlos123]

if there was i would just use that.

[CaptainMorgan]

Then why are you trying to use it?

[carlos123]

is there any method that does the same thing except for a string or int

[CaptainMorgan]

Have you viewed the API ? You still have not understood what I've said - once again:

Quote:

What class is the method parseInt(char) apart of? Once you find that out, you should be able to write the correct code.

To which you replied,

Quote:

there isnt a parseInt(char) method, if there was I would just use that

And yet you appear to already know this - YET you are trying to use it(see the irony there?). Where is parseInt a method of - what class does it belong to? - Answer this with your next post in this thread.

[carlos123]

do you even understand what im trying to do?

[CaptainMorgan]

Carlos - I understand completely, based on what you've written. What you'll learn about me after being here for awhile is that I'm not going to hand you answers - if you want that, please look elsewhere. I'm here to assist you in learning the concepts - which you have failed to do after multiple attempts.

Answer my question above if you want a resolution to your problem.

[carlos123]

ive looked all over the API, i dont think there is a parseint(char) method. is there any other ways around this?

[carlos123]

can you tell me what im doing wrong?

[CaptainMorgan]

Quote:

Originally Posted by carlos123

ive looked all over the API, i dont think there is a parseint(char) method. is there any other ways around this?

That's the point of my previous post - there isn't. With that logic now known, how can you use a method that doesn't exist??

You still have not answered my question. What class does parseInt belong to? Answer - Integer class. Now - find the Integer class within the API. But a char is not what it takes - does it? What possible arguments does it take carlos? Read the API. It's there.

[CaptainMorgan]

Quote:

Originally Posted by carlos123

can you tell me what im doing wrong?

Indeed. You're not taking the initiative to read the API and further - you're not answering questions of those that are trying to help you - me.

And, I've already explained possible solutions - of which you should be able to infer, you're trying to use a method that doesn't exist!

[carlos123]

The parseInt method takes a String, is there any way of NOT getting a char , but instead getting a String.. or converting a char to a string, am i on the right path?

[CaptainMorgan]

Quote:

Originally Posted by carlos123

The parseInt method takes a String, is there any way of NOT getting a char , but instead getting a String.. or converting a char to a string, am i on the right path?

Now I'll confess, I don't understand completely what you just said. I do know based on your original post that this was your problem:

Code:

            int charvalue = parseInt(charat);//error? this is where i need help.

actually, it's pretty obvious - you said this was your error.

Quote:

The parseInt method takes a String

Finally, you read the API..

Quote:

is there any way of NOT getting a char , but instead getting a String..

NOT getting a char? You will not get a char, because the method returns a String. What's not clear here?

[carlos123]

Quote:

import java.util.Scanner;
public class integervaluereader
{
public static void main (String[] args)
{
int zero = 0;
int odd = 0;
int even = 0;
int place=0;
double remain=0;
Scanner scan = new Scanner(System.in);
System.out.println("Enter a number..");
String input = scan.nextLine();
int length = input.length();

// int n = Integer.parseInt(input);

//char charAt(int index)

for(int f=0; f<length; f++)
{
int charat = input.charAt(f);
remain = charat%2;
if (charat==0)
{
zero++;
}
else if (remain!=0)
{
odd++;
}
else if (remain==0)
{
even++;
}


}
System.out.println("zero: "+zero);
System.out.println("even: "+even);
System.out.println("odd: "+odd);



}
}

why do the evens get posted as zeros?

[carlos123]

Quote:

import java.util.Scanner;
public class integervaluereader
{
public static void main (String[] args)
{
int zero = 0;
int odd = 0;
int even = 0;
int place=0;
double remain=0;
boolean zb=false;
Scanner scan = new Scanner(System.in);
System.out.println("Enter a number..");
String input = scan.nextLine();
int length = input.length();

// int n = Integer.parseInt(input);

//char charAt(int index)

for(int f=0; f<length; f++)
{
zb=false;
int charat = input.charAt(f);
remain = charat%2;
if (remain!=0)
{
odd++;
}
else if ((charat == 0) && (remain==0))
{
zb = true;
zero++;
}

else if ((zb == false) &&(remain==0))
{
even++;
}


}
System.out.println("zero: "+zero);
System.out.println("even: "+even);
System.out.println("odd: "+odd);



}
}

Input:444400005555
Output:
Zero:0
Even:8
odd:4

whats wrong?

[CaptainMorgan]

Quote:

Originally Posted by carlos123

why do the evens get posted as zeros?

You're not even getting the numeric values - remember charAt returns the char values. Add the bold line:

Code:

      ... 
      remain = charat % 2;
      charat = Character.getNumericValue(charat);      
      ...

[CaptainMorgan]

The end result looks like this with my formatting(since it wasn't properly formatted - use code tags, not quote tags).

Code:

...
public class integervaluereader {
  public static void main (String[] args) {
    int zero = 0;
    int odd = 0;
    int even = 0;
    double remain = 0;
    
    Scanner scan = new Scanner(System.in);
    System.out.println("Enter a number..");
    
    String input = scan.nextLine();    

    for (int i = 0; i < input.length(); i++) {
      int ch = input.charAt(i);   // returns the char value of the input,
                                  //  thus for the input 34025, you get 
                                  //  char values of 51, 52, 48, 50, 53
                                  //  respectively
      remain = ch % 2;
      ch = Character.getNumericValue(ch);      
      
      if (ch == 0) {
        zero++;
      } else if (remain != 0) {
        odd++;
      } else if (remain == 0) {
        even++;
      }
    }
    
    System.out.println("zero: " + zero);
    System.out.println("even: " + even);
    System.out.println("odd: " + odd); 
  }
}