Pls help "For Loop" Statement example

[tuana]

Hi everybody,

I am new in Java World and I couldn't understand some statements in Java. I couldn't understand the outcome. If you explain that how the outcome is calculated, I' ll appreciate it.

The outcome is : 54 6

public class MixFor5 {

	/**
	 * @param args
	 */
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		int x = 0;
		int y = 30;
		for (int outer = 0; outer < 3; outer++) {
			for (int inner = 4; inner > 1; inner--) {
				x = x + 3;
				y = y - 2;
				if (x == 6) {
					break;
				}
				x = x + 3;
			}
			y = y - 2;
		}
		System.out.println(x + " " + y);

	}

}

[tuana]

[wdh321]

Its quite simple, how many times do you run through each for loop?
Each time you run the outer loop you run the inner loop through however many times it needs to do according to your conditions.
So your inner loop will be running through more times than your outer as for every run through the outer loop, you do a full run through your inner. Im trying my best to explain it without telling you the answer, output is correct though so some simple maths should help get your head around it as well.

[jlczuk]

The for Statement

[Norm]

how the outcome is calculated,

Add println statements to print out the values of variables every time they are changed. The print out will show you the steps the code takes to calculate the output.
For example: System.out.println("x=" + x);

[tuana]

Its quite simple, how many times do you run through each for loop?
Each time you run the outer loop you run the inner loop through however many times it needs to do according to your conditions.
So your inner loop will be running through more times than your outer as for every run through the outer loop, you do a full run through your inner. Im trying my best to explain it without telling you the answer, output is correct though so some simple maths should help get your head around it as well.

hi wdh321,

thank you for your help. According to your explanation, the loop will run 9 times and x will be 6 because of the "break" and then we will multiply 6 and 9 so we can get 54
but how does "y" act?

[tuana]

Add println statements to print out the values of variables every time they are changed. The print out will show you the steps the code takes to calculate the output.
For example: System.out.println("x=" + x);

Hi Norm,
Thank you for your interest bur my problem is not for the "System.out.println" statement, my problem is the calculation...

[Norm]

problem is the calculation.

If you print out what is calculated you will see what the code is doing and how the calculations are done.
If you do any programming, there will be many times when you will need to debug code. One of the oldest ways of debugging code is by using the println statement.

but how does "y" act?

Add some println statements to show how y changes as the code is executed.

[wdh321]

hi wdh321,

thank you for your help. According to your explanation, the loop will run 9 times and x will be 6 because of the "break" and then we will multiply 6 and 9 so we can get 54
but how does "y" act?

Well you have y in both your inner and outer loops.
You already know how many times your inner loop runs, but you also need to consider when y = y-2 will run in your outer loop and how many times.
Like Norm said, if you put println statements in you will be able to see how y is changing and that may help you understand.

[tuana]

If you print out what is calculated you will see what the code is doing and how the calculations are done.
If you do any programming, there will be many times when you will need to debug code. One of the oldest ways of debugging code is by using the println statement.

Add some println statements to show how y changes as the code is executed.

Yes, you are absolutely right.. adding println statement is really useful to understand the calculation.
Thank you..

[tuana]

Well you have y in both your inner and outer loops.
You already know how many times your inner loop runs, but you also need to consider when y = y-2 will run in your outer loop and how many times.
Like Norm said, if you put println statements in you will be able to see how y is changing and that may help you understand.

Thank you so much...