Another problem

[B-52 Stratofortress]

Hello, I am back, I got another issue, please help out :)

import javax.swing.JOptionPane; 

public class Original_16 {


    public void init()
        {
            String number;
            int a; 
            a = Integer.parseInt(JOptionPane.showInputDialog ( " Enter the a 5-digit #: " ));
            
            System.out.println(hello(a));
        }
        
        
    public int hello(int x) {
            int remainder; 
            
            while (x>0) {
                remainder = x%10;
                x = x/10;
                
           }
        }
    return remainder;
}

I am suppose to return the number REVERSED (EX. 123456 -> 654321), which is the value a, any help here?

[DarrylBurke]

How would you do that on paper? Write down the steps and identify the mathematical operations involved.

Then write Java code that performs the same mathematical operations.

db

[B-52 Stratofortress]

Printing it out is easy, but I could figure out how to return the value, am I suppose to write a for loop for it?

[jlczuk]

Why does this have to be a mathematic process? Why can't you just treat it like a string of characters (they happen to be digits)? Trim leading and trailing blanks (look at the methods String provides), and work through the string one position at a time? Yes, you can certainly use a for loop. String has methods to get a character at a specific position, that tell you the length of the string and also to turn a String into a character array, not to mention many other useful methods.

Unless you need to perform mathematic operations on the result, I see not reason to go through such unnatural extents to reverse that number. Even if you need the result as a numeric type in the end, you can use the same technique you used to turn the input string into a number.