Need help to speed up algorithm

[XAW]

Hi. I'm trying to do Sphere Online Judge (SPOJ) - Problem DICTSUB

But I'm getting timeout..So i need to speed up my algorithm. How improve my code or write new better code?

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

class Main {

    public static void main (String[] args) throws IOException {
		BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
		int cases=0;
		int cases2=0;
		String slowo=" ";
		String word=" ";
		int p=0;
		cases=Integer.parseInt(br.readLine());
		for(int i=0; i<cases; i++) {
			if(slowo!=null && slowo.length()>0) {
			slowo=br.readLine();
			p=slowo.indexOf(" ");
			cases2=Integer.parseInt(slowo.substring(0,p));
			word=slowo.substring(p+1);
			for(int k=0; k<cases2; k++) {
			slowo=br.readLine();
			slowo=decode(slowo);
			int pom=0;
			int x=0;
			while(pom!=-1 && x<slowo.length()) {	
				pom=word.indexOf(slowo.charAt(x),pom);
				x++;
			}
			if(pom!=-1) System.out.println("YES");
			else System.out.println("NO");
			
			}
			}
		System.out.print("\r");
		}
	}
	
	public static String decode(String W) {
		char[] array=W.toCharArray();
		StringBuilder ret=new StringBuilder("");
		int pom=0;
		for(int i=0; i<array.length; i++)
			if(i%2==0) pom=array[i];
			else for(int k=0; k<pom; k++) ret.append(array[i]);
		return ret.toString();
	}
	
}

[doWhile]

First, you should define what you mean by 'timeout'. Second, if you wish to speed this up, I recommend profiling your code by timing operations using System.currentTimeMillis - only then will you know which part of your algorithm is the bottleneck so you can focus on that.

[XAW]

SPOJ has time limit for each task. Your code has some time to be performed. We don't know what input author prepared for our algorithm.

The slowest part of my code is comparing strings:

 
            while(pom!=-1 && x<slowo.length()) {
                pom=word.indexOf(slowo.charAt(x),pom);
                x++;
            }

I need faster method to compare strings. But how to do that?

[JosAH]

How, exactly, is a String from the dictionary encoded? You assume an RLE as <len><char><len><char> ... is the <len> a binary encoded number or do you have to read its character representation?

kind regards,

Jos

[XAW]

I could encode "normal" Strings to RLE and then compare but I tried this and it was still too slow..Or did you mean something else?

[Norm]

Cross posted at: Speed Up Algorithm - Java Help - CODECALL