Code

hi all,

i was going through a site consists of scjp questions and i bumped into this

public class Test {
public static void main(String[] args){
int j = 0;
for(; j < 3; j++){
if (j==1) break out;
System.out.print(j + "\n");
}
out:{System.out.println("bye");}
}
}
1. The code will fail to compile.
2. The code will run with no out put
3. This will run and print 0, 1 , 2 and "bye"
4. This will run and print 1 and "bye"

Now it says 1 is the correct answer and the reason it gives is that "This will fail to compile because the labelled block does not enclose the break statement."

But i think 3 is the right answer. What do you all think what the right answer might be??

Thank you and regards

suppose you are a java compiler and you must compile this code. you know that the keyword break or continue can have an argument. now when you arrive to the line with break out you will search for the label out and you will not find it. what will you do? to be a reliable compiler you would throw an error with the message that the label out is missing.

I'm also preparing for the exam. If you have further questions let me know.

Quote:

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Originally Posted by j2me64

suppose you are a java compiler and you must compile this code. you know that the keyword break or continue can have an argument. now when you arrive to the line with break out you will search for the label out and you will not find it. what will you do? to be a reliable compiler you would throw an error with the message that the label out is missing.

I'm also preparing for the exam. If you have further questions let me know.

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thank you and i surely will.

This will break the code i THINK

for(; j < 3; j++){

I'm not very good at Java so I'm not 100% sure tho.

Quote:

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Originally Posted by Tott3

This will break the code i THINK

for(; j < 3; j++){

I'm not very good at Java so I'm not 100% sure tho.

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Nope, the initializer part of the for-loop is optional, so that code is syntactically correct.

kind regards,

Jos