Try and Catch's

[dougie1809]

Hi,

If you have 3 try-catch blocks in a method, and you want to return just one result. how would you go about doing that?
Because I getting an output of three integer outputs, when I only want one integer returned.

Thanks

[MonkeyMan]

Show me some code baby! :)

[pbrockway2]

Because I getting an output of three integer outputs, when I only want one integer returned.

I'm not sure I understand this. Methods, in Java, are constrained to only ever return a single thing: a primitive value (like an int) or a reference value (String etc).

You will get whatever output a method creates - with System.out.println() or similar - and this output has nothing to do with what the method returns.

Perhaps you could post some code that illustrates your problem. Something brief, that compiles but does not do, at runtime, what you intend.

[dougie1809]

Ok. This is the method, but it needs other classes to get it executing, so don't mind what the method does. Code is below:

//Method to get the Process ID of a port number
	public int getPID(String portAdd)
	{
		convertTextFile();
		int pid=0;
		//loop through each line in the text file
		for(String line: textfile) 
		{
  			fields = p.split(line);
		  for(String currField: fields)
		  {
		 		if(portAdd.equalsIgnoreCase(currField))
				{
					try
					{
						String portAddr = fields[KEY_ADDR_P];
  						pid = Integer.valueOf(fields[3]);
  						myPIDs.put(portAddr, pid);
					}
					catch(NumberFormatException nfe)
					{
					}
				}
				
				if(portAdd.equalsIgnoreCase(currField))
				{
					try
					{
						String portAddr = fields[KEY_ADDR_P];
  						pid = Integer.valueOf(fields[4]);
  						myPIDs.put(portAddr, pid);
					}
					catch(NumberFormatException nfe)
					{
					}
					catch(ArrayIndexOutOfBoundsException e)
					{
					}	
				}
				
				if(portAdd.equalsIgnoreCase(currField))
				{
					try
					{
						String portAddr = fields[KEY_ADDR_P];
  						pid = Integer.valueOf(fields[5]);
  						myPIDs.put(portAddr, pid);
						System.out.println(pid);
					}
					catch(NumberFormatException nfe)
					{
					}
					catch(ArrayIndexOutOfBoundsException e)
					{
					}
				}
			}					
		}
		return pid;
	}

So in each if statement is a try-catch block to check it if a portNumber is the same as the number in an array, if not, catch it and do nothing. At least one of the those if statements will be correct and will return the value i need. Instead for an example its returning 0,0,4, where I just want the 4.?

Thanks

[pbrockway2]

Please use code tags.

[dougie1809]

Yes sorry, I always forget using code tags.
But do you understand my problem in the code?

[yellowledbet]

Instead for an example its returning 0,0,4, where I just want the 4

I am confused as an int will not return 0,0,4.

[yellowledbet]

what are these lines supposed to be doing?

		 		if(portAdd.equalsIgnoreCase(currField))
				{
					try
					{
						String portAddr = fields[KEY_ADDR_P];
  						pid = Integer.valueOf(fields[3]);
  						myPIDs.put(portAddr, pid);
					}
					catch(NumberFormatException nfe)
					{
					}
				}

[dougie1809]

Sorry for the confusion. Ive found my problem. Thanks for your help :D

[pbrockway2]

Yes sorry, I always forget using code tags.
But do you understand my problem in the code?

Not really - it really would help if what you posted would compile and if you said exactly what you expected it to output (possibly multiple things) and what it should return (always a single thing). Such a SSCCE takes more work than posting an extract of your code, but it is more productive.

[pbrockway2]

Didn't see your previous post - glad you've got it sorted out.