delimiter breaking the array

[truant420]

Hi java programmers!
I have a problem here using a delimiter. I have the following input:
2
4
1 2 3 (1 2 4 2 4 5)*100 4 5 1
My goal is to get everything inside the brackets and put it into a separate array. I wrote this code:

public static void main(String[] args) throws FileNotFoundException {
		Scanner s = new Scanner(new File("src/input.txt"));
		while (s.hasNext()){
			s.useDelimiter("//()");
		    list.add(s.next());
		}
		
		System.out.println(s.delimiter());
                System.out.println(list);
                System.out.println(list.get(5));

but it produces the error referring to the print statement right above.
Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 5, Size: 1
at java.util.ArrayList.RangeCheck(Unknown Source)
at java.util.ArrayList.get(Unknown Source)
at PagingSystem.main(PagingSystem.java:44)
//()
[2
4
1 2 3 (1 2 4 2 4 5)*100 4 5 1]
It seems to me that it breaks the ArrayList into 3 other arrays. However if I don't use any delimiter the output is this:
[2, 4, 1, 2, 3, (1, 2, 4, 2, 4, 5)*100, 4, 5, 1]
which is what i want it to look like after using the delimiter with the brackets being separate tokens. I don't particularly care about commas. I suppose I'm not using the delimiter properly or I'm not even supposed to use delimiter but I am kind of clueless. Can you help me out?
Many thanks :)

[ozzyman]

I don't think this is a good time to use a delimiter, because in this case it makes your life more complicated.

Here is another way you could do this:

while (s.hasNext()) {
    if (s.hasNextInt()) {
        //add result of s.nextInt() to first array or second array
    }
    if (s == '(') {
        //use the second array
    }
    if (s == ')') {
        //use the first array
    }
}

And here's how you can switch between both arrays when adding the result:

//set to false when you want to use the second array
boolean useFirstArray = true;

String s = "A string";

if (useFirstArray) {
    firstArray.add(s);
} else {
    secondArray.add(s);
}

Note that this is too basic to work with multiple bracket-pairs e.g. 1 2 3 (4 5 (6 7) 8 9)

[truant420]

The reason I was trying to use delimiter in the first place was because the scanner reads the bracket and the integer after it as one token.
1, 2, 3, (1, 2 ...
I tried using your code but it still behaves in the same manner. Any other ideas? How do I make it read the bracket and the number after it separately?

[ozzyman]

Oh right, then use String.contains("(") instead of if s=="(".

private static final String openBracket = "(";
private static final String closedBracket = ")";
private boolean useFirstArray = true;

while (s.hasNext()) {
    if (s.hasNextInt()) {
        //store the number
        storeNumber(s.nextInt());
        continue; //continue if we get the number
    }
    //only come here if we don't get the number
    String str = s.next();
    if (str.contains(openBracket)) {
        //we found an open-bracket, lets get the number attached with it
        String nextIntStr = str.replace(openBracket, "");
        Integer nextInt = Integer.valueOf(nextIntStr);

        //set boolean to use second array
        useFirstArray = false;

        //store the number
        storeNumber(nextInt);
    }
    if (str.contains(closedBracket)) {
        //we found a closed-bracket
        //do something similar to the above, but set useFirstArray to false
    }
}

void storeNumber(int number) {
    if (useFirstArray) {
        //store number in first array
    } else {
        //store number in second array
    }
}