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Thread: Help with loop
 03072012, 04:23 AM #1Member
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Help with loop
The question is:
You can approximate e by using the following series
1+1/1!+1/2!+1/3!+1/4!+⋯
Write a program that finds out how many TERMS of this series you need before you first get 2.71828183 approximately.
I am having troubles writing my actual program. I am trying to loop and test then count until i hit the number but i feel as if my program is not what the question is asking. I get that the question is asking how many terms are needed to find the approximation of e and not the number given because the actual approximation is 2.71828182845904523, which is precise.
Below is my program. I would really appreciate some feedback.
Java Code:public static void main(String[] args) { // TODO Autogenerated method stub double sum=1; double k=1; while (k<=10) { sum=sum+(1/factorial (k)); k++; if (sum>=2.71828183) break; } double term=k1; JOptionPane.showMessageDialog (null,"You need "+term+" terms before you first get 2.71828183 approximately. "); } public static double factorial (double k) { double fact=1; for (double j=1;j<=k;j++) fact=fact*j; return fact; } }
Last edited by pbrockway2; 03072012 at 04:42 AM. Reason: code tags added
 03072012, 04:40 AM #2Moderator
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Re: Help with loop
Assuming that to "first get 2.71828183" means that you first obtain a value between 2.718281825 and 2.718281835 then that is what you should test for. (With a bit of thinking you might be able to simplify the test: but those are the values between which numbers round to 2.71828183.)
 03072012, 04:50 AM #3Member
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Re: Help with loop
how would you obtain the value between 2.718281825 and 2.718281835?
 03072012, 04:52 AM #4Member
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Re: Help with loop
when i compile and run it, it says 10 terms are needed
 03072012, 05:23 AM #5Moderator
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 03092012, 01:51 AM #6Member
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Re: Help with loop
Your while loop stops at when k=10, don't you want it to stop when (sum<e)?
 03092012, 01:52 AM #7Member
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