Newbie Nested Loop Problem

Hi Java Masters,

So I was introduced to nested loops (loops inside the loops). My program will ask the user to pick a number from which pc will pick a number(guess game) and ask you to guess. After you guess it will tell you how many times it took for you to guess and "HERE IS MY PROBLEM" ask you if you want to play again.

So far I was able to create the guess game BUT having troubles with getting to work yes/no. Please see my code below for any clues. I really wish NOT to get a straight answer.... Thank you in advance for all the inputs..... :)

Code:

---

import java.util.Scanner;
import java.util.Random;

public class hw7
{
        public static void main(String[] args)
        {
                Scanner keyboard = new Scanner(System.in);
                Random rand = new Random();
               
                int n;//number of the max guess options
                int guess;//computer magic number of options
                String reply, input;//asks user if want to play again
                int count = 0;//number which will tell us how many times took to guess
       
               
               
                System.out.print("How big of number can I use? ");
                n = keyboard.nextInt();
               
                guess = rand.nextInt(n)+1;//generate n amount of options to guess
               
                while (reply == 'Y')
                {
                do
                {
                        System.out.print("Guess a number from 1 to " + n + " ");
                        guess = keyboard.nextInt();
                       
                        if(guess>n)
                                System.out.println("Try a lower number. ");
                       
                        else if(guess<n)
                                System.out.println("Try a higher number. ");
                               
                        else
                                  System.out.println("Correct");
                       
                        count ++;
                       
                }while (guess!=n);//end of do
               
                System.out.print("You guessed the number on attempt # " + count);
               
                System.out.print("Do you want to play again? (Y/N) : ");
                input = keyboard.nextLine();
                reply = input.chartAt(0);
               
                }//end of while
               
               
               
        }
}

---

OUTPUT:

without second loop program works but after adding second these are my 2 ERROR MESSAGES:

hw7.java:23: incomparable types: java.lang.String and char
while (reply == 'Y')
^
hw7.java:47: cannot find symbol
symbol : method chartAt(int)
location: class java.lang.String
reply = input.chartAt(0);
^
2 errors

OUTPUT WITHOUT 2ND LOOP:


----jGRASP exec: java hw7
How big of number can I use? 3
Guess a number from 1 to 3 1
Try a higher number.
Guess a number from 1 to 3 2
Try a higher number.
Guess a number from 1 to 3 3
Correct
You guessed the number on attempt # 3
----jGRASP: operation complete.

reply is a String variable; 'Y' is a character literal. There's a handful of ways to compare the contents of a String variable. You could use reply.equals("Y"), or you could test a single character using reply.charAt(0) == 'Y'

There's another slight issue I can see off-the-bat as well. The while loop is a pretest loop, meaning that if the condition doesn't exist from the start, the loop will never iterate. You could either initialize reply with "Y", or you could change the while loop to a do-while.

I hope this helps.

Quote:

---

Originally Posted by Jeff_H

reply is a String variable; 'Y' is a character literal. There's a handful of ways to compare the contents of a String variable. You could use reply.equals("Y"), or you could test a single character using reply.charAt(0) == 'Y'

There's another slight issue I can see off-the-bat as well. The while loop is a pretest loop, meaning that if the condition doesn't exist from the start, the loop will never iterate. You could either initialize reply with "Y", or you could change the while loop to a do-while.

I hope this helps.

---

Hi Jeff,

Thanks for your input. I've tried both reply.charAt(0) == 'Y' ^ reply.equals("Y") and in both cases getting this error:

Do you want to play again? (Y/N) : Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 0
at java.lang.String.charAt(String.java:686)
at hw7.main(hw7.java:47)

What am I doing wrong? After the inner loop is done I print outcome of x amount of times till guessed and NOW asking the user to put yes/no where outer loop will go till reply == 'y'? Is the outer group constructed in a bad way or I'm missing something else?

CODE:

Code:

---

  import java.util.Scanner;
  import java.util.Random;

  public class hw7
  {
      public static void main(String[] args)
      {
        Scanner keyboard = new Scanner(System.in);
        Random rand = new Random();
     
        int n;//number of the max guess options
        int guess;//computer magic number of options
        String input;//asks user if want to play again
        int count = 0;//number which will tell us how many times took to guess
     
        char reply;
     
     
        System.out.print("How big of number can I use? ");
        n = keyboard.nextInt();
     
        guess = rand.nextInt(n)+1;//generate n amount of options to guess
     
        do
        {
            do
            {
              System.out.print("Guess a number from 1 to " + n + " ");
              guess = keyboard.nextInt();
           
              if(guess>n)
                  System.out.println("Try a lower number. ");
             
              else if(guess<n)
                  System.out.println("Try a higher number. ");
             
              else
                  System.out.println("Correct");
           
              count ++;
           
            }while (guess!=n);//end of inner do
       
            System.out.println("You guessed the number on attempt # " + count);
            System.out.print("Do you want to play again? (Y/N) : ");
            input = keyboard.nextLine();
            reply = input.charAt(0);       
                 
        }while (reply == 'Y');//outside loop

---

just traced through my code and it appears that my main guess game is incorrect

move the lines:

Code:

---

System.out.print("How big of number can I use? ");
n = keyboard.nextInt();
   
guess = rand.nextInt(n)+1;//generate n amount of options to guess
count = 0; //reset the counter after every game

---

into the outer loop, but before the inner loop. You want the question "How big of a number can I use? " to be displayed every time, as well as the other three lines.

I also changed line 46 to: input = keyboard.next();

After those quick changes, the loops were working well for me :(happy): Well, except for the slight logic error that makes the correct answer the highest possible number.

Quote:

---

How big of number can I use? 4
Guess a number from 1 to 4 4
Correct

How big of number can I use? 3494
Guess a number from 1 to 3494 3994
Correct

---

You're using n as the basis for comparison, and to determine the limiting number of the guessing game. n will always equal the number the user enters.

NOW ive fixed the main code BUT still getting the same error with outside loop ? what am I missing?!?! can I do "do loop in do loop"?

Code:

---

import java.util.Scanner;
  import java.util.Random;

  public class hw7
  {
      public static void main(String[] args)
      {
        Scanner keyboard = new Scanner(System.in);
        Random rand = new Random();
     
        int n;//number of the max guess options
        int guess;//computer magic number of options
        String input;//asks user if want to play again
        int count = 0;//number which will tell us how many times took to guess
              int userGuess;
        char reply;
     
     
        System.out.print("How big of number can I use? ");
        n = keyboard.nextInt();
     
        guess = rand.nextInt(n)+1;//generate n amount of options to guess
     
        do
        {
            do
            {
              System.out.print("Guess a number from 1 to " + n + " ");
              userGuess = keyboard.nextInt();
           
              if(userGuess>guess)
                  System.out.println("Try a lower number. ");
             
              else if(userGuess<guess)
                  System.out.println("Try a higher number. ");
             
              else
                  System.out.println("Correct");
           
              count ++;
           
            System.out.println("You guessed the number on attempt # " + count);
           
            }while (userGuess!=guess);//end of inner do
       
       
            System.out.print("Do you want to play again? (Y/N) : ");
            input = keyboard.nextLine();
            reply = input.charAt(0);       
                 
        }while (reply == 'Y');//outside loop

---

Quote:

---

Originally Posted by Jeff_H

move the lines:

Code:

---

System.out.print("How big of number can I use? ");
n = keyboard.nextInt();
   
guess = rand.nextInt(n)+1;//generate n amount of options to guess
count = 0; //reset the counter after every game

---

into the outer loop, but before the inner loop. You want the question "How big of a number can I use? " to be displayed every time, as well as the other three lines.

I also changed line 46 to: input = keyboard.next();

After those quick changes, the loops were working well for me :(happy): Well, except for the slight logic error that makes the correct answer the highest possible number.


You're using n as the basis for comparison, and to determine the limiting number of the guessing game. n will always equal the number the user enters.

---

yes Jeff, while I was tracing through the code I found out this was an issue. got it fixed now... what is wrong with my outside looP?

Code:

---

System.out.print("Do you want to play again? (Y/N) : ");
            input = keyboard.nextLine();
            reply = input.charAt(0);   
             
        }while (reply == 'Y');//outside loop

---

isn't that should ask the user to put y OR n and the DO LOOP will run till reply == 'y' where is the logic i'm missing.... new to loops :(

Code:

---

import java.util.Scanner;
  import java.util.Random;
 
  public class hw7
  {
      public static void main(String[] args)
      {
        Scanner keyboard = new Scanner(System.in);
        Random rand = new Random();
     
        int n;//number of the max guess options
        int guess;//computer magic number of options
        String input;//asks user if want to play again
        int count = 0;//number which will tell us how many times took to guess
        int userGuess;
        char reply;
     
        do
        {
            System.out.print("How big of number can I use? ");
            n = keyboard.nextInt();
     
            guess = rand.nextInt(n)+1;//generate n amount of options to guess
            count = 0; //reset the counter after each game
            do
            {
              System.out.print("Guess a number from 1 to " + n + " ");
              userGuess = keyboard.nextInt();
           
              if(userGuess>guess)
                  System.out.println("Try a lower number. ");
               
              else if(userGuess<guess)
                  System.out.println("Try a higher number. ");
               
              else
                  System.out.println("Correct");
           
              count ++;
           
            System.out.println("You guessed the number on attempt # " + count);
           
            }while (userGuess!=guess);//end of inner do
         
         
            System.out.print("Do you want to play again? (Y/N) : ");
            input = keyboard.next();
            reply = input.charAt(0);   
             
        }while (reply == 'Y');//outside loop
      }
  }

---

I moved a few lines and added count = 0; to the outer loop to reset after each game. I also changed input = keyboard.nextLine(); to input = keyboard.next();. It's working for me.

I understand your frustration completely :(happy): if you need me to explain why I made the changes I did, feel free to ask.

Jeff,

Why did you change input = keyboard.nextLine(); to input = keyboard.next(); ???? - my wild guess would be since I've specified that input is String I don't need "Line" or what???

I also had to move System.out.println("You guessed the number on attempt # " + count); OUTSIDE of the while because otherwise it would print SOP where it NOT supposed to. so why did nextLine VS next makes a difference?

My Final Code:

Code:

---

  import java.util.Scanner;
  import java.util.Random;

  public class hw7
  {
      public static void main(String[] args)
      {
        Scanner keyboard = new Scanner(System.in);
        Random rand = new Random();
     
        int n;//number of the max guess options
        int guess;//computer magic number of options
        String input;//asks user if want to play again
        int count = 0;//number which will tell us how many times took to guess
        int userGuess;
        char reply;
     
     
        do
        {
            System.out.print("How big of number can I use? ");
            n = keyboard.nextInt(); 
            guess = rand.nextInt(n)+1;//generate n amount of options to guess
            count = 0;
                 
            do
            {
              System.out.print("Guess a number from 1 to " + n + " ");
              userGuess = keyboard.nextInt();
           
              if(userGuess>guess)
                  System.out.println("Try a lower number. ");
             
              else if(userGuess<guess)
                  System.out.println("Try a higher number. ");
             
              else
                  System.out.println("Correct");
           
              count ++;
           
           
            }while (userGuess!=guess);//end of inner do
            System.out.println("You guessed the number on attempt # " + count);
           
            System.out.print("Do you want to play again? (Y/N) : ");
            input = keyboard.nextLine();
            reply = input.charAt(0);       
                 
        }while (reply == 'Y');//outside loop
                     
     
     
      }
  }

---

Because keyboard.nextLine() sees the white space (the enter, return, or carriage return. whichever term you prefer) that occurs when the user enters a guess. I might be a little off on my explanation, but if you would like a visual example of this, try running:

Code:

---

import java.util.Scanner;
  import java.util.Random;
 
  public class HW7
  {
      public static void main(String[] args)
      {
        Scanner keyboard = new Scanner(System.in);
        Random rand = new Random();
     
        int n;//number of the max guess options
        int guess;//computer magic number of options
        String input;//asks user if want to play again
        int count = 0;//number which will tell us how many times took to guess
        int userGuess;
        char reply;
     
        do
        {
            System.out.print("How big of number can I use? ");
            n = keyboard.nextInt();
     
            guess = rand.nextInt(n)+1;//generate n amount of options to guess
            count = 0; //reset the counter after each game
            do
            {
              System.out.print("Guess a number from 1 to " + n + " ");
              userGuess = keyboard.nextInt();
           
              if(userGuess>guess)
                  System.out.println("Try a lower number. ");
               
              else if(userGuess<guess)
                  System.out.println("Try a higher number. ");
               
              else
                  System.out.println("Correct");
           
              count ++;
           
            System.out.println("You guessed the number on attempt # " + count);
           
            }while (userGuess!=guess);//end of inner do
         
         
            System.out.print("Do you want to play again? (Y/N) : ");
            input = keyboard.nextLine(); //replaced keyboard.next() with two .nextLine()'s
            input = keyboard.nextLine();
            reply = input.charAt(0); 
             
        }while (reply == 'Y');//outside loop
      }
  }

---

You'll find that it runs the same as a single .next()

[QUOTE=Jeff_H;269824]Because keyboard.nextLine() sees the white space (the enter, return, or carriage return. whichever term you prefer) that occurs when the user enters a guess. I might be a little off on my explanation,/QUOTE]

yes still little bit confused.... :( Thx a bunch for all of your HELP JEFF