Printable View
Hello everyone, I'm starting to learn Java (only had 1 class till now but I already got some programs to work on) so bare with me.
My question is :
long i =Integer.parseInt(args[0]);
When I have this,
1. What does long mean ?
2. What's the whole Integer.parseInt(args[0]) part for ?
When I compile the program, I gotta write it like this {"5"} or else it won't work.
I have a function apart that does the factorial of a number so that's what the program is about.
Any help ?
Cheers!
A long is like an int but it takes eight bytes so it can store much larger numbers. That args[0] mumbo jumbo converts a String (the first command line argument args[0]) to an int. You'll learn all about it in the next lessons.
kid regards,
Jos
Thanks Jos.
I've understood the long part.
About the args[0] what will it convert to an int in this case ?
What's the purpose of using it in this case ?
Cheers!
The 'args' array is an array of Strings; it contains the command line arguments, so args[0] is the first command line argument (if it exists).Quote:
Originally Posted by JeremyLin
kind regards,
Jos
Hmm, thanks.Quote:
Originally Posted by JosAH
I don't think there exists any command line argument though :o
I mean, I do compile it using {"7"} so I'm guessing that would convert "7" to 7 right ?
Right; if there are no command line arguments the expression args[0] would cause your program to throw an ArrayIndexOutOfBoundsException and stop. Your version simply converts the String "7" to an int (which is 7 of course).Quote:
Originally Posted by JeremyLin
kind regards,
Jos
Alright.
Thanks a lot Jos, I'll be posting some doubts I may have later :p
Cheers!