Need help with sin in java

[Zeronitic]

I'm working sin in java but I have a issue.
How can I get rid of the unnecessary zero's in my program.

This is how it is supposed to end up.

Angle  Sin
-90.0	 -1.0
-75.0	 -0.965926
-60.0	 -0.866025
-45.0	 -0.707107
-30.0	 -0.5
-15.0	 -0.258819
0.0	 0.0
15.0	 0.258819
30.0	 0.5
45.0	 0.707107
60.0	 0.866025
75.0	 0.965926
90.0	 1.0

Here is how mine ends up.

Angle    Sin
-90.0    -1.000000
-75.0    -0.965926
-60.0    -0.866025
-45.0    -0.707107
-30.0    -0.500000
-15.0    -0.258819
0.0    0.000000
15.0    0.258819
30.0    0.500000
45.0    0.707107
60.0    0.866025
75.0    0.965926
90.0    1.000000

Here is my code.

import java.text.*;
public class prog232 {
public static void main(String[] args){
	double a,b;
	  DecimalFormat numform = new DecimalFormat("0.000000");
	a = -105.0;
while (a <= 75){
a = a + 15;
b = Math.sin(Math.toRadians(a));
System.out.println("" + a + "    " + numform.format(b));


}
}
}

[Fubarable]

Please Google and read up on the limitations of using digital hardware to represent floating point numbers and you'll see why your request is not trivial. Also, personally, I like your out better than the first output.

[Zeronitic]

Nevermind. It was actually very trivial and I figured it out.

[DarrylBurke]

Ah, ok, sine. I thought someone was looking for a confessional here

db