Adding odd numbers

This is probably something very basic, but I can't for the life of me think of how to get this to work.

What I need to do is prompt the user for a positive integer(n), then add n odd numbers together (eg: n=4; add 1+3+5+7 = 16)

I know I need to loop through 4 times: for(int i = 0; i < n; i++)
I can add up sequential numbers, just can't seem to get it right when I only need odd numbers.

I'm stuck on this problem, can someone help me with this?

Thanks!

If you have to loop n times, the largest number in your loop is 2*n-1 (check this); you only want to do odd numbers so you have to start at one (1) with an increment of 2; so:

Code:

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for (int i= 1; i <= 2*n-1; i+= 2)
  // do your dirty deed here ...

---

But, if you apply a bit of math, you don't have to loop at all; adding the numbers 1+3+5+ ... +2*n-1 is n*n

kind regards,

Jos

yeah, I understand that this is just squaring the N number, but here's the question I'm trying to answer:

Quote:

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Write a program that reads in a positive integer N and then calculates and displays
the sum of the first N odd integers. For example, if N is 4, your program should
display the value 16, which is 1 + 3 + 5 + 7.

---

I'm trying to answer this by printing out the loop (ex: i = 0 and total = 1, i = 1 and total = 3, i = 2 and total = 5, i = 3 and total = 7) Then I'll have a separate variable to add total for find the final answer of 16.

I want to break it down into the it's smallest parts so I can get a better understanding of why and how it's doing what it's doing.

Quote:

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Originally Posted by kmlam585

yeah, I understand that this is just squaring the N number, but here's the question I'm trying to answer:



I'm trying to answer this by printing out the loop (ex: i = 0 and total = 1, i = 1 and total = 3, i = 2 and total = 5, i = 3 and total = 7) Then I'll have a separate variable to add total for find the final answer of 16.

I want to break it down into the it's smallest parts so I can get a better understanding of why and how it's doing what it's doing.

---

See the loop in my previous reply.

kind regards,

Jos

Thanks for the help! I was thinking about it completely wrong.

Code:

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import acm.program.*;

public class AddOddInts extends ConsoleProgram {

    public void run() {
        int n = readInt("Enter a positive integer: ");
        int total = 0;
        for (int i = 1; i <= 2 * n - 1; i++) {
            if (i % 2 != 0) {
                total += i;
                //println(i + " Odd " + total);
            }
        }
        println(total);
    }
}

---

Almost perfect; if i is an odd number, then i+2 also is an odd number. You can change your loop to this:

Code:

---

for (i= 1; i <= 2*n-1; i+= 2)
  total+= i;

---

Variable i only has odd values so you can skip the test in the body of your for loop.

kind regards,

Jos

ahhh, ok that makes sense to me. I was doing a lot of this, but not putting it together correctly. I see how it works now though.

thanks for your help JosAH!