problem with split method

[abhiN]

Hi

i m using split methos and want to display string elements seperatly..

String quoteValues = ";;12";
String[] quote = quoteValues.split(";");
for(int i=1 ; i<quote.length ; i++)
{
if(quote[i] != "")
System.out.println(" quote--"+quote[i]);
}

but i m getting output--
quote--
quote--12

i want only to get--
quote--12

how to get..
plz reply..

[roots]

if(!quote[i].equals(""))

Pointer: ==, is String a native type ??

[CaptainMorgan]

The split method recognizes your token, in this case ';' and prints out the strings before or after it, if they exist - but not including the token. So after reading the first token, it looks to see surrounding strings, and finds ";12" - thus it finds another token which it can't print resulting in the undesired output. From there, I assume you know how split() operates. The pattern you're looking for is to exclude empty strings, thus:

String[] quote = quoteValues.split(";+");

Hope this helps. :)

[abhiN]

thanks..it works.. my simple mistake..

[knkhadanga@yahoo.com]

I have used the split API with "|" and i am not getting the proper result.
Can somebody tell me why..
the sample code is given under

public static void main(String[] args) {


String a = "a|c|d|e";
String b[] = a.split("|");

for(int i=0; i<b.length; i++){
System.out.print(b[i]+" ");
}
System.out.println(b.length);


}

and the result i got is:
a | c | d | e 8

any idea abt this?

[CJSLMAN]

Your problem is that "|" is a regex metacharacter:

The metacharacters supported by this API are: ([{\^-$|]})?*+.

Try replacing "|" with "\\|"
Here's a good guide for regex:

Lesson: Regular Expressions (The Java™ Tutorials > Essential Classes)

Luck,
CJSL

PS: Please open your own post... don't post on other old posts.

[knkhadanga@yahoo.com]

Thanks.... It worked after using the "\\|" in split

[MK12]

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