How do I convert a Big-Endian(64 bit) to Little Endian(64 bit) in Java.

Hi,

How do I convert a big-endian(64 bit) to little endian(64 bit) in Java and vice versa.

For e.g. I have 40429C28F5C28F5C in big endian, I want to convert it into little endian (5C8FC2F5289C4240) and vice versa.


How would I code a function to do this in Java?

Thanks.

Sukhpreet Kaur

This topic interests me as it brings me back to my Assembly programming days... check out here which may hint at a solution...

Something like the following may be helpful and was taken from here:

Code:

---

[FONT=tahoma,arial,sans-serif][SIZE=-1][COLOR=#000000]import java.nio.ByteOrder;

public class Endian {
  public static void main(String argv[]) {
    ByteOrder b = ByteOrder.nativeOrder();
    if (b.equals(ByteOrder.BIG_ENDIAN)) {
      System.out.println("Big-endian");
    } else {
      System.out.println("Little-endian");
    }
  }
}
[/COLOR][/SIZE][/FONT]

---

Another solution is found here, although doesn't look 64-bit...

Let us know your final result.

Hi CaptainMorgan,

Thank you for your help and the links you've posted.

I am looking for something Java CodeGuru: Deal with big-endian and little-endian order
but this example code is for 4-bytes, I am looking something for 8 bytes(64-bits) where I can enter (40429C28F5C28F5C) as an argument and the function can return (5C8FC2F5289C4240) ...

Any suggestions/help will be appreciated.

Thank you.

The code is shown below:

[/code]

public static long bigToLittleEndian(long bigendian) {
ByteBuffer buf = ByteBuffer.allocate(8);

buf.order(ByteOrder.BIG_ENDIAN);
buf.putLong(bigendian);

buf.order(ByteOrder.LITTLE_ENDIAN);
return buf.getLong(0);
}


public static void main(String[] args) {
long res = bigToLittleEndian(0x40429C28F5C28F5CL);
System.out.println(Long.toHexString(res));
}

[/code]

Thank you.