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Thread: Triangle
 01132008, 09:17 PM #1Member
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 01132008, 09:29 PM #2
You've got pretty detailed instructions  there shouldn't be much confusion on your part, break out the old algebra/trig book and get started. I mean, you've even got a runner class that implies the output you're supposed to receive.. think about this for a second, how difficult can this be?
Btw, thanks for the message  but you're better off posting a thread such as you did here and chances are you'll get more responses, unless I was the only one you messaged. I'm not interested in doing other people's work, but I am interested in helping others learn the language. Your problem is not a Java problem, but a motivational problem. Why do you believe you can't do this?Vote for the new slogan to our beloved Java Forums! (closes on September 4, 2008)
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 01132008, 09:33 PM #3Member
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I don't really understand much java. I just need to hear what format to put it in..
(if statement..etc.)Last edited by jkswebsite; 01142008 at 12:33 AM.
 01132008, 09:34 PM #4
Then start here.
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 01142008, 01:40 AM #5Member
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this is the most recent code I have. I'M SO CLOSE!
/**
* Class triangle
*/
public class Triangle {
private int a;
private int b;
private int c;
/**
* Default constructor that creates an equilateral Triangle with side length
* 1.0
*/
public Triangle() {
a = (int) 1;
b = (int) 1;
c = (int) 1;
}
/**
* Another constructor that takes three int parameters that will be the
* three side lengths. It must validate the three parameters that they can
* actually form a triangle. (recall from Geometry: the sum of any two sides
* of a triangle must be greater than the third side) The constructor must
* throw an IllegalArgumentException if the parameters are invalid.
* @return
*
* @return
*/
public Triangle(int d, int e, int f) {
if (d + e > f && e + f > d && f + e > d) {
a = d;
b = e;
c = f;
} else {
throw new IllegalArgumentException("cannot form a triangle with values "+ a +","+ b +","+ c);
}
}
/**
* Method called getLongestSide that takes no parameters and returns the
* value of the longest side length. (i.e. the greatest of a,b, and c)
*/
public int longestSide() {
if (a >= b && a >= c)
return a;
else if (b >= a && b >= c)
return b;
else
return c;
}
/**
* Method called isRightTriangle that takes no parameters and returns true
* if the Triangle, (whose sides are a,b, and c) form a right triangle and
* returns false otherwise. (hint: use Pythagorean Theorem and recall the
* longest side is the hypotenuse)
*/
public boolean isRightTriangle() {
if (a * a + b * b == c * c)
return true;
else
return false;
}
/**
* Method called scalar that takes an int parameter and converts this
* Triangle to a similar Triangle by multiplying each side length by the
* parameter.
*/
public void scalar(int i) {
a = a * i;
b = b * i;
c = c * i;
}
/**
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
* BONUS! * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
*
*/
{
/**
* Method called isCongruentTo that takes a Triangle parameter and
* returns true if all three 'corresponding' sides are equal, and
* returns false otherwise. (example: 3,4,5 is congruent to 3,5,4 but
* not congruent to 3,3,5)
*/
// INSERT CODE HERE
}
{
/**
* Write a method called area that returns the area of this Triangle
*/
// INSERT CODE HERE
}
}
1
5
6
false
true
false
10
50
60
false
true
false
this is the output you're SUPPOSED to get:
1
5
6
false
true
false
10
50
60
false
true
false
Exception in thread "main" java.lang.IllegalArgumentException: cannot form a tri
angle with values 3,9,4Triangle t4 = new Triangle(3,9,4);
any ideas?Last edited by jkswebsite; 01142008 at 02:15 AM.
 01142008, 02:55 AM #6Member
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I Got It!!!! Thanks!!
 01142008, 03:33 AM #7
I haven't read over your final result, but I'll assume that you got it correct and are satisfied with your work. Congratulations on figuring it out and I hope that maybe you learned that this can be fun, if not now maybe you will in the near future. :) Aren't you glad you figured it? Deriving the solution for oneself is typically found to be more fun than acquiring the solution from someone else.
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 01102009, 02:00 PM #8Member
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hiiii all....
I am new to this community ....n java too....
I m so eager too learn it.....:)
 01102009, 02:08 PM #9Member
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