show elements in correct order

[Shien]

So I have two arrays with values iArray {A,C,E,B,H,C,B,F,D} and tArray{M,D,F,E,M,H,C,A,K}
My code shows results like this (if I choose letter B):
E,F
C,D
H,M

But it shoud be like this:

E,F,A,M
C,D,K
H,M

Can you tell me how to fix it?

for(int z = 0; z < counter; z++)
                    {
                        c:
                        for(int i = 0; i < counter; i++)
                        {
                            fta = iArray[i];
                            sta = tArray[i];
                            if(fta.equals(oldsta))
                            {
                                textArea2.append(sta+" ");
                                oldsta = sta;
                                oldfta = fta;
                                kk++;
                                finalArray[i] = tArray[i];
                                index = i;
                                iArray[i] = "0";
                                tArray[i] = "0";
                                break c;
                            }
                            else if(sequence.equals(fta))
                            {
                                if(index != 0)
                                {
                                    textArea1.append(finalArray[index]+"\n");
                                    textArea2.append("\n"+sta+" ");
                                    oldsta = sta;
                                    oldfta = fta;
                                    kk++;
                                    finalArray[i] = tArray[i];
                                    index = i;
                                    iArray[i] = "0";
                                    tArray[i] = "0";
                                    break c;
                                }
                                else{
                                    textArea2.append(sta+" ");
                                    oldsta = sta;
                                    oldfta = fta;
                                    kk++;
                                    finalArray[i] = tArray[i];
                                    index = i;
                                    iArray[i] = "0";
                                    tArray[i] = "0";
                                    break c;    
                                }
                            } 
                            else{
                                loop:
                                for(int ii = 0; ii < kk; ii++)
                                {
                                    if(fta.equals(oldfta))
                                    {
                                        textArea1.append(finalArray[index]+"\n");
                                        textArea2.append("\n"+tArray[i]+" ");
                                        oldsta = tArray[i];
                                        finalArray[i] = tArray[i];
                                        index = i;
                                        iArray[i] = "0";
                                        tArray[i] = "0";
                                        break loop;
                                    }   
                                }
                                }
                        }
                    }
                    textArea1.append(finalArray[index]+"\n");

[JosAH]

So I have two arrays with values iArray {A,C,E,B,H,C,B,F,D} and tArray{M,D,F,E,M,H,C,A,K}
My code shows results like this (if I choose letter B):
E,F
C,D
H,M

But it shoud be like this:

E,F,A,M
C,D,K
H,M

Why should it be like that? Can you tell us the reason why?

kind regards,

Jos

[Shien]

I am writing program wich would show a path from letter you entered to the point it ends. So that is why there is 2 arrays: if array and then array;
It's kinda similar to a tree. you go from a top down. In example above I showed how it should be.

Sorry I am a bit rusty on my english so I can't explain this very well :/

[JosAH]

I'd iterate over the iArray, trying to find a wanted symbol and I'd recurse over both arrays to find and print the nodes on a current 'branch'.

kind regards,

Jos

[ozzyman]

Your code is very hard to follow written like this. if you compartmentalised it that would make it easier to follow. anyhow, i had a look at your code and i understand what you are trying to do.

1. Given a letter in the first array, get the index of that letter in the second array

public int getPath(char c, char[] iArr, char[] tArr) {
    int index = Arrays.binarySearch(iArr, c);
    if (index>=0) return Arrays.binarySearch(tArr, c);
    return index;
}

2. Handle char not found

int index = getPath('b', iArr, tArr);
if (index >= 0) {
    //continue
} else {
    //end
}

3. Set up a recursive method to explore one path

public void explorePath(char c, char[] iArr, char[] tArr) {
    //find the char in iArr
    ...
    //if found, output the char and recurse
    ...
    System.out.print(newChar);
    explorePath(newChar, tArr, iArr);
    //if not found end the output
    System.out.println();
}

I dont know if my logic is exactly right to your need but hopefully you get the idea of what I'm trying to explain (in my defense i'm answering from my smartphone and this site isnt very mobile friendly).