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 12232011, 09:25 PM #1Senior Member
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 12232011, 09:39 PM #2
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Re: How would you solve this? Java coding for multiplication.
It cannot be solved because the righrmost digit in the fourth row has to be a zero.
kind regards,
JosI have the stamina of a seal; I lie on the beach instead of running on it.
 12232011, 09:41 PM #3Senior Member
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Re: How would you solve this? Java coding for multiplication.
What makes you think that?
I am sure it is a "can be solved" question.
 12232011, 09:59 PM #4Moderator
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Re: How would you solve this? Java coding for multiplication.
 12232011, 10:02 PM #5Senior Member
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 12232011, 10:08 PM #6
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Re: How would you solve this? Java coding for multiplication.
The last digit of the top two numbers have to be a 3 and a 5 (...3x..5 = ....5 (or ..5x.3 = ....5 is the only possibility), so the last digit of the result is 5 as well. Maybe consistent reasoning like this can help you to solve this puzzle. If there are too many alternatives I'd take the lazy approach (brute force)
kind regards,
JosI have the stamina of a seal; I lie on the beach instead of running on it.
 12232011, 10:11 PM #7Senior Member
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Re: How would you solve this? Java coding for multiplication.
I am trying to solve it with Java :)
Thanks though... :)
I have this idea of looping for all numbers in the first 2 rows and multiplying them and to check if they are all prime numbers(2,3,5,7)..
But can there be a better approach ?
 12232011, 10:15 PM #8Moderator
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Re: How would you solve this? Java coding for multiplication.
Totally slow answer adding nothing removed.
@OP: That's more or less what I would do.Last edited by pbrockway2; 12232011 at 10:17 PM.
 12232011, 10:30 PM #9
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Re: How would you solve this? Java coding for multiplication.
There are four different digits (2, 3, 5 and 7) so you should count in base 4. There are 4x4x4 possible first numbers and 4x4 possible second numbers. You can try them all after mapping 0 > 2, 1 > 3, 2 > 5 and 3 > 7 and see which numbers have the correct result.
kind regards,
JosI have the stamina of a seal; I lie on the beach instead of running on it.
 12232011, 10:34 PM #10Senior Member
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