Quick question.

[juxta]

Hi guys, I have a quick question. (Sorry, I'm not very good at for-loops)

In this code:

int value [] = {0};

for (int counter =0; counter < value.length; counter++){
System.out.print(counter + value[counter]);
System.out.print(counter + value[counter]);
System.out.print(counter + value[counter]);
System.out.print(counter + value[counter]);
System.out.print("\n");
}


It prints out 0000. I want it to repeat it again on the next line. Is there an efficient way of doing it?
Thanks.

[CodeAdmiral]

try changing each System.out.print to System.out.println (LN)
That should create a new line each time an output occurs.

[KevinWorkman]

Word to the wise- use more descriptive titles.

What exactly do you want it to repeat on the next line? Another four zeroes? Or each zero on its own line? And what do you mean by efficient?

[juxta]

Word to the wise- use more descriptive titles.

What exactly do you want it to repeat on the next line? Another four zeroes? Or each zero on its own line? And what do you mean by efficient?

Yeah, another four zeros. Sorry about that.

[CodeAdmiral]

My example will make a 0 on each line.

[sunde887]

Put a loop inside a loop. The outer loop will produce the inner loop n times. Here is an example

for (int i = 0; i < 10; ++i){
  for (int i = 0; i < someLength; ++i){
    do something
  }
}

[al_Marshy_1981]

.........

[CodeAdmiral]

Then make a loop with what you want repeated inside.

[al_Marshy_1981]

I think a ternary if inside a System.out.print might get it down to one line in the for loop.

[juxta]

Put a loop inside a loop. The outer loop will produce the inner loop n times. Here is an example

for (int i = 0; i < 10; ++i){
  for (int i = 0; i < someLength; ++i){
    do something
  }
}

With the letter 'i', wouldn't that be 'counter' from my code??

[juxta]

With the letter 'i', wouldn't that be 'counter' from my code??

Ignore that. Thanks sunde

[Junky]

int value [] = {0};

Using an array to store a single element is pointless.