Quick Java Help

[EdOBannon]

For the following code how would I EXIT the program? If the input is equal to 3 I need to exit the program.

import java.util.Scanner; // needed to import Scanner class  
import java.util.ArrayList;
  
public class cpb09eTestDrive_A5 {  
    // Create Scanner  
    private static Scanner scan = new Scanner(System.in);  
    //Program Execution  
    public static void main(String[] args) {  
    	
    	ArrayList<cpb09eEmployee_A5> emplist = new ArrayList<cpb09eEmployee_A5>();
        
    	    	
    	//Prompt  
        System.out.println("Please indicate the type of employee by typing its number: ");  
        System.out.println("1 - Wage Worker");  
        System.out.println("2 - Executive");  
        System.out.println("3 - Exit");  
        //Read  
        
        String input = scan.nextLine();  
  
        if(input.equals("1")){  
            //create WageWorker object  
        	
        	cpb09eEmployee_A5 obj = new cpb09eEmployee_A5(); 		// create employee object and initialize it	
			
        	cpb09eWageWorker_A5 wage = new cpb09eWageWorker_A5();
          		
			System.out.println("Enter the Objects Name ");
          		String Name = scan.next();			// input name from user
          		wage.SetName(Name);					// set the name in employee class
          		
          			
          		System.out.println("Enter the Wage  ");
          		int Wage = scan.nextInt();			// input wage from user
          		wage.SetWage(Wage);   				// set wage of employee	

          		System.out.println("Enter the Hours ");
          		int hours = scan.nextInt();        // input hours from the user
          		wage.SetHours(hours);               //set the hours
          		
          		wage.SetSalary(hours * Wage);			// calculate and set the salary
          		
          	    emplist.add(wage);             		// set the object in array list
          	    
          	      	
        }  
        
        else if(input.equals("2")){  
            //create Executive object  
        	
        	cpb09eEmployee_A5 obj = new cpb09eEmployee_A5();	
    		
        	cpb09eExecutive_A5 exe_obj = new cpb09eExecutive_A5();
        	
        	System.out.println("Enter the Objects Name ");
        		String Name = scan.next();				
        		exe_obj.SetName(Name);					
        		
        	System.out.println("Enter the Salary ");
        		int Sal = scan.nextInt();				
        		exe_obj.SetSalary(Sal);					
        		
        	System.out.println("Enter the Title ");
        		String title = scan.next();        	
        		exe_obj.SetTitle(title);				
        	
        	emplist.add(exe_obj); 					
        	
       		
        }  
        
        else if(input.equals("3")){  
            //exit the program  
        }  
    }  
}

[Cosmos]

maybe its weird but it is as simple as this-

just write System.exit(0);

[pbrockway2]

Did you see the answers given in your other thread? And understand them?

That code doesn't need any change in order to exit if the user enters "3". And, please use "code" tags when you post code.