While condition/math series.

[tnrh1]

Ok it's working, amazing .. after 2 weeks I got a damn answer.

Although post #5 shows the way.

What is this post #5 you always mention?

And I do not understand the logic behind the action, do you?

I feel liberated, this Enigma which is no longer an enigma chased me for the last 2 weeks!
Thanks again.

[JosAH]

What is this post #5 you always mention?

All replies in a thread are numbered; look at the right side of the replies.

kind regards,

Jos

[pbrockway2]

Post #5 was just a suggestion that you view the problem a little differently. You asked, in effect, "how big must the triangle be to accomodate n numbers?" I suggested making a copy of the triangle (or use a mirror) and putting the two together to form what is almost a square. Then the question becomes "how big must the almost-square be to accomodate n pairs of numbers?"

Works for me, anyway. Although, as Jos might have guessed, I threw the first couple of hundred values of n into Excel, checked the rounded value, and called it done. (After all, it's not *my* problem!) Simplifying the problem involves a mirror, but proving the result might require a smoke...

[pbrockway2]

Post #5 was just a suggestion that you view the problem a little differently. You asked, in effect, "how big must the triangle be to accomodate n numbers?" I suggested making a copy of the triangle (or use a mirror) and putting the two together to form what is almost a square. Then the question becomes "how big must the almost-square be to accomodate n pairs of numbers?"

Works for me, anyway. Although, as Jos might have guessed, I threw the first couple of hundred values of n into Excel, checked the rounded value, and called it done. (After all, it's not *my* problem!) Simplifying the problem involves a mirror, but proving the result might require a smoke...

[JosAH]

Post #5 was just a suggestion that you view the problem a little differently. You asked, in effect, "how big must the triangle be to accomodate n numbers?" I suggested making a copy of the triangle (or use a mirror) and putting the two together to form what is almost a square. Then the question becomes "how big must the almost-square be to accomodate n pairs of numbers?"

Works for me, anyway. Although, as Jos might have guessed, I threw the first couple of hundred values of n into Excel, checked the rounded value, and called it done. (After all, it's not *my* problem!) Simplifying the problem involves a mirror, but proving the result might require a smoke...

... and an espresso! The trouble comes when you want to find a close form for a number n, f(n) is the line for number n; you have to solve two quadratic inequalities ... I don't like those, so I'm happy with your guess ;-)

kind regards,

Jos

[tnrh1]

Thanks for both of you for helping me,
it helped me alot.

hmm .. case closed I guess

[pbrockway2]

You're welcome.