Modifying a String of 10 digits

[ljd0991]

Hi again.

suppose my program reads in a string from the user. The string represents a 10 digit codword

an example input would be:

0079584584

I now run a series of equations to determine if any character's need changing. possibilities are:

1) no characters need replacing
2) 1 character needs replacing
3) two characters need replacing


So supposed my equations determined that 1 character need replacing. say this character was the 7 in the above String of 10 digits and it needed replacing with a 9 to create a valid 10 digit codeword.

how do i go about this?

I have researched and i dont think the String.Replace() will work with this?

[JosAH]

You can get the characters in a String with the toCharArray() method. You can later (after changing one or more characters in the array) build a String out of the char array again.

kind regards,

Jos

[ljd0991]

okay so my String which reads in the 10 digits is called 'input'

I am trying your way so i have:

char[] arr = input.toCharArray();

I have an int 'i' - which represents the position of the error. so the digit that needs replacing is at index: (i-1) because indexing starts at 0 obviously and 'i' only represents the position i.e. 1st digit, 2nd digit, 3rd digit, etc. rather than the actual index.

and i have an int called 'modified' which represents the new value that needs to be put in the string.

How do i now put 'modified' in at index (i-1), replacing the original value

I hope this makes sense

[JosAH]

okay so my String which reads in the 10 digits is called 'input'

I am trying your way so i have:

char[] arr = input.toCharArray();

I have an int 'i' - which represents the position of the error. so the digit that needs replacing is at index: (i-1) because indexing starts at 0 obviously and 'i' only represents the position i.e. 1st digit, 2nd digit, 3rd digit, etc. rather than the actual index.

and i have an int called 'modified' which represents the new value that needs to be put in the string.

How do i now put 'modified' in at index (i-1), replacing the original value

I hope this makes sense

That is elementary programming; read any textbook on Java programming (it should be somewhere in the first chapters).

kind regards,

Jos

[ljd0991]

Are you still suggesting the toArrayChar way then?

Its just my Lewis and Loftus Java Software Solutions book doesnt have anything on this.

And i cant find anything online using toArrayChar() and replacing.

[JosAH]

Are you still suggesting the toArrayChar way then?

Its just my Lewis and Loftus Java Software Solutions book doesnt have anything on this.

And i cant find anything online using toArrayChar() and replacing.

Throw that book away then, it lacks the explanation of the most simple Java stuff:

char[] c= s.toCharArray();
int i= ...; // the position of the char to change
c[i]= ...; // change it
s= new String(c); // build a new String

kind regards,

Jos

[ljd0991]

My idea was create an array with the 10 integers

d1 = Integer.parseInt(String.valueOf(input.charAt(0)));
d2 = Integer.parseInt(String.valueOf(input.charAt(1)));
d3 = Integer.parseInt(String.valueOf(input.charAt(2)));
d4 = Integer.parseInt(String.valueOf(input.charAt(3)));
d5 = Integer.parseInt(String.valueOf(input.charAt(4)));
d6 = Integer.parseInt(String.valueOf(input.charAt(5)));
d7 = Integer.parseInt(String.valueOf(input.charAt(6)));
d8 = Integer.parseInt(String.valueOf(input.charAt(7)));
d9 = Integer.parseInt(String.valueOf(input.charAt(8)));
d10 = Integer.parseInt(String.valueOf(input.charAt(9)));

[]d = {d1, d2, d3, d4, d5, d6, d7, d8, d9, d10};

and replace one of those with the new value

but again there is not alot of information about on replacing values in arrays with new ones.

The ArrayList uses the simple .add() and .remove() but i think this going way off the point of my task.

[ljd0991]

Sorry, didnt see your post.

[ljd0991]

Im trying to replace it with an int and it seems your way requires a char value.

int modified = Integer.parseInt(String.valueOf(input.charAt(i-1))) + a;
char[] c = input.toCharArray();
c[i-1]= modified; // change it
input = new String(c); // build a new String


I am getting possible loss of precision, required: char dound : int

regards

[JosAH]

Im trying to replace it with an int and it seems your way requires a char value.

int modified = Integer.parseInt(String.valueOf(input.charAt(i-1))) + a;
char[] c = input.toCharArray();
c[i-1]= modified; // change it
input = new String(c); // build a new String


I am getting possible loss of precision, required: char dound : int

Yup, a char array can only store chars as its elements, so you should cast your int value to a char type:

c[i-1]= (char)modified; // change it

kind regards,

Jos

[ljd0991]

Thanks, i actually researched this but there are a lot of pages saying the converted int will just be the ASCII value rather than converting the int "1" to a char "1"

I will try this

[JosAH]

Thanks, i actually researched this but there are a lot of pages saying the int will just be the ASCII value of the char rather than converting the int "1" to a char "1"

I will try this

Hold on for a second, you started this thread claiming that one char needs to be replaced with another char; that's exactly what my method does; all the rest are details ;-)

kind regards,

Jos

[ljd0991]

Will that way not work then mate?

[JosAH]

Will that way not work then mate?

Sure, pay close attention:

String s= "123";
char[] c= s.toCharArray();
c[2]= '9';
s= new String(c);
System.out.println(s);

Play a bit with this bit of code and see for yourself.

kind regards,

Jos