Problem with a password

[saytri]

I'm having a problem with a password. The password is an integer, but my problem is that when someone tries to enter a string input, the program crashes, instead i want it to display invalid like when someone tries to enter an invalid integer password. I also wish to display the password in asterik form. What do i have to do? Can someone pls help me? Thanks a lot! The code i've written is below:-

Code:

import javax.swing.*;
 
import java.awt.*;
import java.awt.event.*;
import java.util.*;
 
import java.io.*;
 
import java.util.Scanner;
import java.util.Arrays;
 
public class GeographyQuiz extends JFrame implements ActionListener {
 
  private static final int FRAME_WIDTH = 140;
  private static final int FRAME_HEIGHT = 160;
  private static final int FRAME_X_ORIGIN = 70;
  private static final int FRAME_Y_ORIGIN = 50;
 
   AnswerStore answerStore = new AnswerStore();
  
  public static void main (String[] args) {
 
    JFrame jFrame;
    jFrame = new JFrame();
 
    JOptionPane.showMessageDialog(jFrame, "This is a Geography Quiz");
    JOptionPane.showMessageDialog(null, "Good Luck");
 
    char choice;
    int i, choice1, Password;
    String yourChoice, passString;
 
    passString = JOptionPane.showInputDialog("Enter the Password");
 
    //Password = passString.nextInt();
    Password = Integer.parseInt(passString.trim());
 
    if (Password == 123) {
     JOptionPane.showMessageDialog(null, "Valid. You typed the right password. Now choose from the following menu");
 
     GeographyQuiz frame = new GeographyQuiz();
      frame.setVisible(true);
 
    } else {
      JOptionPane.showMessageDialog(null, "Invalid Password. Try Again");
    }
  }
}

[wsaryada]

First, to hide the password you can use the JPasswordField swing component.

Second, to prevent your program from crashing you need to catch the NumberFormatException when you parse the input string to interger value, because the parseInt() method of the Integer class throws this exception if the input is not a valid number.

[saytri]

Ok thanks. :-)