Find character at the end of the string with regex

I have a simple regex that I cant get to work, it is supposed to check that the last character in a string is an integer.

String myString = "dst760.log.092211.233116";
if(myString.matches("\\d$")
{
do something
}
else
{
do something else
}

The format of the string changes but the only thing I want to check is the last character. I have tried a few iterations without any success here are a few of them ("[0-9]$")("^*.[\\d+]$") and few more that I cant remember.

You shouldn´t use matches( ... ) because it tries to match the entire String against the regular expression. Use find() and read the API documentation for the Matcher class.

kind regards,

Jos

Thanks for pointing me in the right direction, I will try find().

Quote:

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Originally Posted by samnjugu

Thanks for pointing me in the right direction, I will try find().

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Of course you can also do without those nasty regular expressions; have a look:

Code:

---

boolean isLastDigit(String s) {
  if (s == null || s.length() == 0) return false; // no last digit in here
  char l= s.charAt(s.length()-1); // the last char
  return Character.isDigit(c);
}

---

kind regards,

Jos

Hi Jos, I have been using a method almost exactly as yours, after having no success with the regex as for some reason my matcher class does not have a find() method. In my version since I check for null before calling this method I have just shrunk it to a oneliner.

Code:

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static boolean lastCharIsDigit(String string)
    {                       
                return Character.isDigit(string.charAt(string.length() - 1));
           
    }

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Thanks for the help.