If Statement Modification (Using String Methods)

[Norm]

Look at what you are printing. There are two indexes: one in the word, one in the vowels.

print out the value of i also.

[danthegreat]

String word = "Daniel";        String vowels = "AaEeIiOoUu";




        
        for(int i=0; i<vowels.length(); i++){//loop through all the letters
            


            if(word.indexOf(vowels.charAt(i))!=-1){


                System.out.println(word.indexOf(vowels.charAt(i)));
                i=word.length();
            }






        
}

Ok so I got the right code in my test. However, when I try to translate 'beams' instead of finding index of 1, it displays 2. Why is it skipping the e, it should be checking it. It seems to be looking for A's first and then E's. How can I make it so it shows the earliest one in word rather than the earliest vowel the computer checks?

[Norm]

What does the value 2 represent?

What are you doing with the value of i: i=word.length()
Why are you setting it to this value?
What value of i is tested in the for statement?

[danthegreat]

2 represents the 'a' found. I realize that the computer is searching by the order of the string 'vowels'. If it finds an A anywhere in the string, then it will stop the loop without searching for earlier vowels.

How can I make it so the computer checks the earliest vowel in string 'word' rather than checking the earliest vowel in string 'vowels'?

[Norm]

2 represents the 'a' found.

That is not clear since 'a' is in both the word String and the vowels String.
A clearer way to say this is that 2 is the index into one of these String: word or vowels

[Norm]

What are you doing with the value of i: i=word.length()
Why are you setting it to this value?
What value of i is tested in the for statement?

[danthegreat]

sorry that was a typo its vowels.length()

[Norm]

You need to define what you are trying to do. You seem to be going this way and that way.
Do you want the index of the first vowel in the String word? or what?
What variable has the index of the letters in the String word?

Do you want to know if the String word has a vowel?
The return true if so and false if not.

[danthegreat]

I figured it out: (This is my final hasAVowel() Function) -

public static int hasAVowel(String word){//detects if the word has a vowel and returns location

    
        int index=0, pos=999;
        String vowels = "AaEeIiOoUu";


                
        for(int i=0; i<vowels.length(); i++){//loop through all the letters
            


            if(word.indexOf(vowels.charAt(i))!=-1){
                
                if(pos>=word.indexOf(vowels.charAt(i))){
                    pos=word.indexOf(vowels.charAt(i));
                }
        


            }
        


        }    
        
        index=pos;


        return index;
}

pos is a new variable that makes sure the earliest vowel is saved. For example: "Beams"

the computer finds 'a' at pos1 = 2. However, there is an 'e' in front of it which is the FIRST OCCURRENCE. Then, the computer checks for the e's and finds that 'e' is at pos1 = 1. Then the if statement checks if pos1>pos2, save the earliest occurrence of a vowel. It then saves pos = 1 because it is earlier than pos =2.

[Norm]

What if you took a letter in word one at a time and tested if it was in the vowels String?
If the letter is in vowels then the index into word for the letter found in vowels would be what you returned.