Logical Operator query

[aconti]

Hello,

why does the below work correctly only with the || operator as I thought that I should use the && operator

import java.util.Random;


public class Dice {

	/**
	 * @param args
	 */
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		
		int dice1;
		int dice2;
		int count;
		int totalcount = 0;
		
		
		do{
			Random rand = new Random();
			
			dice1 = rand.nextInt(6) + 1;
			
			dice2 = rand.nextInt(6) + 1;
			
			System.out.println("Dice1 " + dice1);
			System.out.println("Dice2 " + dice2);
			
			count = dice1 + dice2;
			
			totalcount = totalcount + 1;
			
			
			
			System.out.println("Count for this throw is " + count);
			
			
			
		[B]}while(dice1 != 1 || dice2 != 1);[/B]
		
		System.out.println("");
		System.out.println("");
		
		System.out.println("You have obtained the Snake Eyes by doing a total count of " + totalcount);
			
		
			
	
		

		
		
		
		
		
	}

}

[Norm]

why does the below work correctly only with the || operator as I thought that I should use the && operator

(dice1 != 1 || dice2 != 1)

Define what "work correctly" means?
Please explain what the conditions are that you want the condition to be true?
Make a truth table listing all the values for the two die with the desired results.

[aconti]

Hi Sorry I just want the do while loop to stop if both dices numbers are 1 only

[Junky]

It seems the code works. So what is your problem?

[DarrylBurke]

Hi Sorry I just want the do while loop to stop if both dices numbers are 1 only

So you do want the loop to continue as long as either of the dice is not 1.

db

[Tolls]

Or, put another way, you want to exit the loop when both dice equal 1:
dice1 == 1 && dice 2 == 1
which means to continue the loop you want that to be false:
!(dice1 == 1 && dice 2 == 1)
which is, of course, the logical equivalent to the OR one you have in your functioning code.