stuck on this pls help(validation and char.toString)

[xLrak]

we were asked by our professor to do a simple class wherein we need to make it ask the user to enter the first name middle name and last name so i came up with the class like this:

import java.io.*;
public class StringManipulation {
	public static void main(String args []) throws IOException {
		
		BufferedReader dataIn=new BufferedReader(new InputStreamReader(System.in));
		
		try {
			System.out.print("Enter First Name: ");
			String k = dataIn.readLine();
		
			System.out.print("Enter Middle Name: ");
			String j = dataIn.readLine();
			String m = Character.toString();
		
			System.out.print("Enter Last Name: ");
		 	String s = dataIn.readLine();
		
		System.out.println(k + " " + j + " " + s);		
		}catch(Exception m) {
			m.printStackTrace();
		}		

	}
}

the output is always like this:

Enter First Name: John
Enter Middle Name: Jhay
Enter Last Name: Smith
Your Name Is: John Jhay Smith

but then after that when i showed it to her she wants me to make the final output to be like this:

Enter First Name: John
Enter Middle Name: Jhay
Enter Last Name: Smith
Your Name Is: John J. Smith

how can i make it like that? i used char.toString code but i always come up with an error and no matter what i do i can't seem to fix it.

also she wants me to make a validation code for it where in the user can only input alphabets and the special characters "." and "-" i tried using if(!Character.isDigits()) but still gives out an error .. can anyone help?

[eRaaaa]

String m = Character.toString(); <-- what ?
You could use charAt(0) to get the first Character, thats what you want or?
char m =j.charAt(0);
....
System.out.println(k + " " + m + ". " + s);

For the other one you could use regex,something like if(k.matches("[a-zA-Z\\.-]+")).....

[Junky]

Character.toString();

The toString method will convert a char to a String which is not what you want. Even if it was, which char is it supposed to convert to a String? Did you look at the API to see what parameters that method has?

if(!Character.isDigits())

Once again did you read the API to see if the Character class has that method. You cannot just make up method names.

but still gives out an error

In future copy and paste the full and exact error message so we can see it. We don't read minds.