A little confused by this tiny program...

This is the program:

Code:

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public class EchoText
{
  public static void main(String[] args) throws java.io.IOException
  {
      System.out.println("Please enter some text and press Enter!");
      int ch;
      while ((ch = System.in.read()) != 13)
        System.out.print((char) ch);
      System.out.println();
  }
}

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The part that confuses me is in the while loop...
basically, i tye in "a"
then "b" it waits till I hit enter... then prints out "ab"
how come "ch" is not getting overwritten on every keypress?
I mean how come it does not only print out the last character (in this case it woud be "b")

I dont see any concatenation above...

Is this what you mean?

Code:

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public static void main(String[] args) throws java.io.IOException
          {
           
              Scanner myScanner = new Scanner(System.in);
              int ch;
              System.out.println("Please enter some text and press Enter: ");
             
            if(myScanner.findInLine(".").charAt(0) != 13){               
                    ch = myScanner.nextInt();
                    System.out.println(ch);
              }
          }

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Quote:

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how come "ch" is not getting overwritten on every keypress?

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The OS doesn't send any input to the read routine until Enter is pressed. Then it sends the whole line.

Quote:

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I dont see any concatenation above

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The print() method you are using does not go to the next line after printing. So all the chars are on the same line.
Change it to println() and the characters will be on separate lines

Quote:

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Originally Posted by Norm

The OS doesn't send any input to the read routine until Enter is pressed. Then it sends the whole line.

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Ah! That makes sense now, thanks!