Random Number Generator with User Input

Hi,
I'm new to Java and I'm making a really simple random number generator, but I also want for the user to be able to choose the maximum number e.g. Random Number between 1-100, but the problem is I'm not sure of how to say it's an integer field, and I know that java is probably expecting that it'd be like 3 * hello which wouldn't work. Currently I've got the code;

Code:

---

import java.util.Scanner;

public class ChoiceofRandomNumber
{
    public static void main(String[] args)
    {
        Scanner r = new Scanner(System.in);
        System.out.println("What's the Maximum Number you Want to be Possible?");
        String name = r.nextLine();
        System.out.println((int) (Math.random() * r) +1);
    }
}

---

I'm guessing that this'll be a really easy fix but I'm not exactly sure where to go. Thanks for your help.

Code:

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int myInt = r.nextInt();

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Is that what you're trying to do? Make a scanner input that only accepts integers?

Yeah that's exactly it! Thanks for the quick response.

Ok well 11 minutes isn't really slow, you could have found this out even faster by using Google. What I like to do, and actually how I found what you were looking for was by using Google.

I typed in "Scanner class java 6 api" and this is the first link that showed up:
Scanner (Java Platform SE 6)

Even better: download the entire API documentation from this link. It isn't much (mega-byte size speaking) but it's valuable stuff and having it all available (even off-line) takes away all those lame excuses where people simply guess, try and hope for the best. b.t.w. the download link can be found in the left margin, down the page.

kind regards,

Jos

@JosAH, good idea. I can't do that right now, but is there a search feature in the offline version?

Quote:

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Originally Posted by Dark

@JosAH, good idea. I can't do that right now, but is there a search feature in the offline version?

---

afaik, the off-line version is identical to the on-line version (only faster, depening on your connection speed).

kind regards,

Jos

Downloading now (56.4MB) but the server seems to be quite slow. Thanks again.

Ok, thanks JosAH. I will keep that in mind for future reference.

Code:

---

import java.util.*;
class Random1
{
public static void main(String args[])
{
Random ar=new Random();
Scanner read=new Scanner(System.in);
int n;
System.out.println("Enter min value");
int min=read.nextInt();
System.out.println("Enter max value");
int max=read.nextInt();
if(max==min)
    System.out.println("Random number between "+min+ "-" +max+" is "+max);
do
{
n=ar.nextInt(max);
if(n>=min)
System.out.println("Random number between "+min+ "-" +max+" is "+n);
}
while(n<min);
}
}

---

Why dont you look at the above code.I am also new to JAVA and like to wite programs.Though i know it's bit complex code which i have written but i have just given a try.Pls do comment about it.:)-:

I don't know if you are looking for help or spoon-feeding, if the former, please make your own thread, otherwise, don't spoonfeed! Also, if you do post code, use code tags, not quote tags

[code]
YOUR CODE HERE
[/code]

Hey , i am new to this forum ,I just joined today so was not knowing it and yes i am not seekin for any help ,i was just helping the thread owner to have look at the code whether it was this ,he was looking for and yes next time will use that code tag :(devil):

Quote:

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Originally Posted by djscorpio99

Code:

---

import java.util.*;
class Random1
{
public static void main(String args[])
{
Random ar=new Random();
Scanner read=new Scanner(System.in);
int n;
System.out.println("Enter min value");
int min=read.nextInt();
System.out.println("Enter max value");
int max=read.nextInt();
if(max==min)
    System.out.println("Random number between "+min+ "-" +max+" is "+max);
do
{
n=ar.nextInt(max);
if(n>=min)
System.out.println("Random number between "+min+ "-" +max+" is "+n);
}
while(n<min);
}
}

---

Why dont you look at the above code.I am also new to JAVA and like to wite programs.Though i know it's bit complex code which i have written but i have just given a try.Pls do comment about it.:)-:

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That is a very inefficient solution. On average it'll take max/(max-min) iterations (for min < max) to find an appropriate pseudo random number.

kind regards,

Jos

That's fine to be new, but it will help the user if you just tell him what to use and let him do the work. For instance, on this Problem he will probably want to use Scanner, Random, and a loop, which can all be easily found in the API.

Other than that, have fun here and don't get offended if people correct you.

If you want to find a range you will want to find a number from ((max-min)+1)+min.

If min is 20, max is 40, you would find numbers in the range 0-20(40-20 + 1) and add 20 to it.

Code:

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nextInt(21); //generates numbers from 0(inclusive) to 21(exclusive)

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Hey JoSah, thanks for pointing out the inefficient complexity , i would take care of it in future for sure :(happy):

&

@sunde887 ,thanks for yours suggestion too.Now no offence now onwards:(clap):