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 05242011, 08:17 PM #1Member
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help with permutations of a string
hello, im working on a word scrambling program that will generate all the possible formations of the inputed letters, i have most of the code done i just cant figure out how to solve the rest of it.
here is what i have so far
Java Code:public class Scramble { public static void main(String args[]) { permuteString("", "it"); } public static void permuteString(String beginningString, String endingString) { if (endingString.length() <= 1) System.out.println(beginningString + endingString); else for (int i = 0; i < endingString.length(); i++) { String newString = endingString.substring(0, i) + endingString.substring(i + 1); permuteString(beginningString + endingString.charAt(i), newString); } } }
it
ti
but i also need "t & i" by themself
any ideas?
 05242011, 09:02 PM #2
Can you explain the logic you are using to generate the output?
 05242011, 09:40 PM #3Member
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it starts by printing out the word
that was first originally entered, then it switches the last and 2nd to last character then the 2nd to last and the 3rd to last and soo forth until that character is the 2nd character, then it does the same until the last charcter is now the 3rd.
once that process completes the original 2nd letter becomes the first and the original 1st becomes 2nd and the previous process repeats
then the original 3rd becomes 1st and the origianl 2nd becomes 3rd and the process repeats
let me know if you need more detail
 05242011, 09:53 PM #4
How does that algorithm produce Strings shorter than the original?
 05252011, 07:15 PM #5Member
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thats what the problem is, it doesn't and i need to help making it do so.
 05252011, 07:26 PM #6
Add additional calls to the method with 1 at a time, then 2 at a time, then 3 at a time etc
 05252011, 07:28 PM #7
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Your problem is a combined problem; one solution runs as follows:
1) generate all combinations C(i, n) for 1 <= i <= n, e.g for the String "abc" you generate the following:
C(1, 3): a, b, c
C(2, 3): ab, ac, bc
C(3, 3): abc
2) next you generate all permutations for all String above:
P(C(1, 3)): a, b, c
P(C(2, 3)): ab, ba, ac, ca, bc, cb
P(C(3, 3)): abc, acb, bac, bca, cab, cba
All the Strings from step 2) are the Strings that you want.
kind regards,
Joscenosillicaphobia: the fear for an empty beer glass
 05252011, 07:33 PM #8Member
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ok so the first time i can pass all the letters then then all the letters 1 then again with a different combo of letters untill its complete and store everything in the possible combinations array
 05252011, 07:35 PM #9Member
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