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[nalinda]

given a sequence of letters, and an array that has a random sequence of letters in each element, how do i find if any of the elements match the given sequence, and which element number it is at?
i.e:given "abcdefg" , String [] array = {bfg, fgj, cde, efg, ght} , how do i say that cde and efg are inside that sequence?

[staykovmarin]

You can always use a regex. If you dont know what a regex is, i strongly suggest you read Lesson: Regular Expressions (The Java™ Tutorials > Essential Classes)

                // all the patterns that are going to have to be matched
		String [] array = {"bfg", "fgj", "cde", "efg", "ght"}; 
		Matcher m;
		// scans trough each pattern
		for(int i = 0; i < array.length; i++) {
                        // creates a new pattern for each element in the array
			Pattern p = Pattern.compile(array[i]);
                        // attepts to match the created pattern to the specified string
			m = p.matcher("abcdefg");
                        // if the pattern matches: print
			if (m.find())
				System.out.println(array[i] + " is contained");
		}

[nalinda]

i see what u mean...but how would i do it using indexOf?

[staykovmarin]

Here is a simpler way, although less powerful, it might be better suited for whatever you are doing.

		String [] array = {"bfg", "fgj", "cde", "efg", "ght"}; 
		String toTest = "abcdefg";
		for(int i = 0; i < array.length; i++) {
			if (toTest.contains(array[i])) 
				System.out.println(array[i] + " is contained");
		}