Command to return the path the class is curently in.

[stchman]

Hello all.

This is my first post.

I need to be able to return the path the class is running from.

This is what I have come up with:

import java.util.*;
import java.io.*;

public class ReturnPath {
    public static void main( String[] args ) {
        ReturnPath m = new ReturnPath();
        m.getPath();
    }

    public void getPath() {
        File f = new File( "" );
        
        String pathName = f.getAbsolutePath();
        
        System.out.println( pathName );
    }
}

This appears to work, does everyone agree with what I have done.

[ra4king]

Another way is:

System.getProperty("user.dir");

[DarrylBurke]

That will give the path to the folder/package of that specific class.

No, it'll give the path of the current working directory.

If you want the path to the folder/package of the main program class, you would do:

System.getProperty("user.dir");

No, that'll give the path to the user's home directory, which has nothing to do with where the .class file is located.

db

[ra4king]

@Darryl.Burke
No "user.dir" returns the "User's current working directory".
"user.home" returns the user's home directorr.
System (Java Platform SE 6))

But you are quite correct on the first statement. I got confused with something else, the OP's way works too.

[pbrockway2]

Of "user.dir":

No, that'll give the path to the user's home directory, which has nothing to do with where the .class file is located.

Umm, well, ...

@OP: See for yourself. Compile and run this all over the place to see what these things give you.

import java.io.File;

public class Test {
    public static void main(String[] args) {
        System.out.println(new File("").getAbsolutePath());
        System.out.println(System.getProperty("user.home"));
        System.out.println(System.getProperty("user.dir"));
    }
}

[Edit] slow ;( But it is a good idea to try these things out, follow up on the API docs etc.

[r035198x]

... I need to be able to return the path the class is running from.
..

Why do you need to do this?

[DarrylBurke]

@Darryl.Burke
No "user.dir" returns the "User's current working directory".
"user.home" returns the user's home directorr.

Oops, sorry about that.

db

[stchman]

Of "user.dir":




Umm, well, ...

@OP: See for yourself. Compile and run this all over the place to see what these things give you.

import java.io.File;

public class Test {
    public static void main(String[] args) {
        System.out.println(new File("").getAbsolutePath());
        System.out.println(System.getProperty("user.home"));
        System.out.println(System.getProperty("user.dir"));
    }
}

[Edit] slow ;( But it is a good idea to try these things out, follow up on the API docs etc.

I ran the following program:

import java.util.*;
import java.io.*;

public class ReturnPath {
    public static void main( String[] args ) {
        ReturnPath m = new ReturnPath();
        m.getPath();
    }

    public void getPath() {
        File f = new File( "" );
        String pathName = f.getAbsolutePath();
        
        System.out.println( pathName );
        System.out.println( System.getProperty( "user.home" ) );
        System.out.println( System.getProperty( "user.dir" ) );

    }
}

Here is the output:

/media/storage/java_progs
/home/bob
/media/storage/java_progs

Apparently System.getProperty( "user.dir" ) will give me what I want.

Thanks all.

[ra4king]

Glad to help :)