Very new to Java, simple problem..

[RattleSnake]

Hi guys,

I just started learning Java last night and based on what I learned I tried to make a program.. It works, but it doesn't work.

Here's the source code (using Eclipse, if it matters):

WeightChecker.java:

class WeightChecker {

int age;
int weight;
boolean isHazim;
String name = "Hazim";

	void checkPerson() {
	if (!name.equals("Hazim")) {
		isHazim = false;
		System.out.println("Imposter detected!");
	} else if (name.equals("Hazim")) {
		isHazim = true;
		}
	
	}
	
		void checkWeight() {
		if (weight == 10);
			System.out.println("Weight determined! It is indeed Hazim!");
		} 
		
		void checkWeight2() {
		{
		if (weight == 100);
			System.out.println("Weight determined. Person is too fat.");
	}

		}
}

VerifyName.java:

class VerifyName {
	public static void main(String[] arguments) {
	WeightChecker hazim = new WeightChecker();
	hazim.isHazim = false;
	hazim.name = "Hazim";
	hazim.weight = 10000;
	
	hazim.checkPerson();
	hazim.checkWeight();
	hazim.checkWeight2();
	}
	

}

So.. I initiated an instance, starting at 10,000 weight, and then I called the checkWeight and apparently, if the weight is equals to 10, then it should print:

Weight determined! It is indeed Hazim!

But if the weight equals to 100, then it should print:

Weight determined. Person is too fat.

However, when I ran the script in Eclipse, this was my output..

Weight determined! It is indeed Hazim!
Weight determined. Person is too fat.

Why :(

[JosAH]

When you type in your ten thousand, don't type a comma, i.e. 10000 instead of 10,000; those commas are Locale bounded.

kind regards,

Jos

[doWhile]

Don't add a semicolon after your if statements...it causes the conditional to terminate, and the next line will be evaluated independent of the conditional if statement.

[goldest]

You are ending your if statements with a semicolon ; which makes the next print statements as standalone statements. And thats why they print just as if they were called directly. There is no weight validation there.

Have an habit of using curly braces with your if statements. Like,

if (weight == 100) {
	System.out.println("Weight determined. Person is too fat.");
}

Hope that helps,

Goldest

[RattleSnake]

Great - thanks a lot, works like a charm.

Another question..

How can I combine these two statements:

		void checkWeight() {
		if (weight <= 141)
			System.out.println("Weight determined! It is indeed Hazim!");
		} 
		
		void checkWeight2() {
		{
		if (weight >= 140)
			System.out.println("Weight determined. Person is too fat.");
	}

		}

To an else-if method?

I tried this but Eclipse says it's wrong.. :(

		void checkWeight() {
		if (weight <= 141)
			System.out.println("Weight determined! It is indeed Hazim!");
		else if { (weight >= 140)
			System.out.println("Weight determined. Person is too fat.");
		}

[sunde887]

if(condition){
  Statements
}
else if(condition){
  Statements
}

[JosAH]

[code]
if(Condio
Statements

I've got it: you're typing this on your cell phone; clean your keypad ;-)

kind regards,

Jos

[sunde887]

I've got it: you're typing this on your cell phone; clean your keypad ;-)

kind regards,

Jos

Lol, indeed, accidentally hit the done button and it removed the keyboard and I hit submit. Damn iPhone keyboard.

[RattleSnake]

I was playing around and I removed a bracket and this seems to work well..

		void checkWeight() {
		if (weight <= 141)
			System.out.println("Weight determined! It is indeed Hazim!");
		else if (weight >= 140)
			System.out.println("Weight determined. Person is too fat.");
		}

However, howcome this method compiles fine and there's a bracket with the else if?

	void checkPerson() {
	if (!name.equals("Hazim")) {
		isHazim = false;
		System.out.println("Imposter detected!");
	} else if (name.equals("Hazim")) {
		isHazim = true;
		}
	
	}

[sunde887]

Every clause in the if else clause has a statement(or a statement block). It may be a good habit to wrap all of your conditionals statements in blocks.

[goldest]

It may be a good habit to wrap all of your conditionals statements in blocks.

Rightly said!

OP,

Have a look at this nice article which will make the things more clear for you.

Working with if-else statements

Goldest

[RattleSnake]

Awesome! That made things a lot clearer.

I have one more question.. I'm not sure what it's called.. But what is the "and" in Java?

Like I want to do:

void FinalResult() {
if (name == Hazim) & (age == 15) & (weight = 140)
System.out.println("Final result determined! It is Hazim!)"
}

How could I do that?

[goldest]

You are talking about bitwise AND operator "&"

Read some good documentation of Java operators, there are many.

Here is one good link : Java Operators Tutorial

Hope that helps,

Goldest

[JosAH]

Lol, indeed, accidentally hit the done button and it removed the keyboard and I hit submit. Damn iPhone keyboard.

Stupid iPhones; I don't want to type on a vacuum cleaner either; those devices aren't made for the job; here, have a look at this real device. Now that's what I call a device.

kind regards,

Jo