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Thread: communicate with xml-rpc
- 04-17-2011, 09:43 PM #1
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communicate with xml-rpc
hello everyone i want to communicate with xml-rpc in my code but i can't! and get error when i compile my code.
my code
i get this error when i compile my code!Java Code:package com.thr.FireEagle; import java.net.MalformedURLException; import org.apache.xmlrpc.XmlRpcException; import org.apache.xmlrpc.client.XmlRpcClientConfigImpl; import java.net.URL; import org.apache.xmlrpc.client.XmlRpcClient; //import java.util.Vector; public class JavaClient { private static Object[] params; public JavaClient( ) { params = new Object[] { "http://dl4.mihandownload.com/2011/Alipour0c/2011.4/Welcome_MAC_World_Mihandownload.com.rar" }; } public static void main( String[] args ) { System.out.println( "execute" ); XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl(); try { config.setServerURL(new URL("http://127.0.0.1:6800/rpc")); } catch (MalformedURLException e) { // TODO Auto-generated catch block e.printStackTrace(); } XmlRpcClient client = new XmlRpcClient(); client.setConfig(config); try { client.execute("aria2.addUri", params ); } catch (XmlRpcException e1) { // TODO Auto-generated catch block e1.printStackTrace(); } } }
error occurred at line:Java Code:execute org.apache.xmlrpc.XmlRpcException: URI is not provided. at org.apache.xmlrpc.client.XmlRpcStreamTransport.readResponse(XmlRpcStreamTransport.java:197) at org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:156) at org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143) at org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:69) at org.apache.xmlrpc.client.XmlRpcClientWorker.execute(XmlRpcClientWorker.java:56) at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:167) at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:137) at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:126) at com.thr.FireEagle.JavaClient.main(JavaClient.java:29)
but i don't no how to fix it!Java Code:client.execute("aria2.addUri", params );
unfortunately aria2 has the method aria2.addUri but i surprised what in code i can't communicate with aria2!
please help me to fix this problem.
- 04-18-2011, 04:06 PM #2
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No everyone can help me?
- 04-18-2011, 09:14 PM #3
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