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- 11-28-2007, 06:10 PM #1
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- 11-28-2007, 07:22 PM #2
Java Code:String s = "The StringTokenizer methods do not distinguish " + "among identifiers, numbers, and quoted strings, " + "nor do they recognize and skip comments; it is " + "a legacy class."; System.out.println("s = " + s); String delims = " ,;"; StringTokenizer tokens = new StringTokenizer(s, delims); while(tokens.hasMoreTokens()) System.out.println(tokens.nextToken());
- 11-29-2007, 09:38 AM #3
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Perfect. It worked. Thanks.
I have another question. What if my token is composed of more than one characters?
Output:Java Code:String s= "I am new to Java. Are you good in Java, if yes please help me."; String delim = "Java"; StringTokenizer tokens = new StringTokenizer(s, delim); while(tokens.hasMoreTokens()) System.out.println(tokens.nextToken());
Actually "Java" is not treated as a token but 4 different tokens (each character is a token). How to handle this?Java Code:Welcome I m new to . Are you good in , if yes ple se help me.
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