String problem: deleting

[BlueBird]

I got this program in my practical paper. We were asked to input a string like "try (a) checking (b)" and print "TRY CHECKING"
I managed to get my output as "TRY ) CHECKING". I'm copying a part of my code. Any suggestions on how to eliminate the remaining parentheses will be great!
code:

public void check()
{
len=n.length();

for(int i=0;i<len;i++)
{
ch=n.charAt(i);
if((ch!='(')||(ch==' '))
{
temp=temp+ch;
store=temp.toUpperCase();
}
else if(ch=='(')
{
do
{
store1=store1+ch;
i++;
}
while((n.charAt(i+1)!=')'));
}
}
System.out.println("String:"+store);
}

n is my original string, temp, store and store1 are extras for storing the changes in n.

[sanjeevtarar]

Is this input "try (a) checking (b)" is fixed or it can be changed like

try (c) checking (f) and so on

[Tolls]

public void check()
    {
        len=n.length();
        
        for(int i=0;i<len;i++)
        {
            ch=n.charAt(i);
            if((ch!='(')||(ch==' '))
            {
                temp=temp+ch;
                store=temp.toUpperCase();
            }
            else if(ch=='(')
            {
                do
                {
                    store1=store1+ch;
                    i++;
                }
                [B][U]while((n.charAt(i+1)!=')'));[/U][/B]
            }
        }
        System.out.println("String:"+store);
    }

In that underlined bolded bit your comparison is looking ahead to the next character.
The loop exits when that character is the close bracket.
Then you go back to the for loop, and i is incremented and you are now looking at the close bracket, which you then append to your result.

You want to do..while until the acharacter at index i is not equal to the close bracket. Not i + 1.

[BlueBird]

Oh! :P Ofcourse! Thanks a lot. :P