Problems with readLine() and calling methods

[peachyco]

Hi, y'all!

I'm new to the forums, and also to Java programming. I'm trying to write a Cash Till program for a project but I keep having a problem with my input.

Code:

//Main Method
public static void main(String[] args)
{
	userVerify();
	
	drawMainMenu();
	userInput();
		
	while (inputStr != "1" && inputStr != "2")
	{
		System.out.println("\n--------------------------"	+
						   "\nERROR: Input Out of Range."	+
						   "\n--------------------------\n\n");
		drawMainMenu();
		userInput();
	}
		
	//DUMMY EFFECTS: This part includes what happens
        //  after the selection is made.
	System.out.println(inputStr);
	System.exit(0);
		
}//end main

.
.
.

//Method to acquire input from user
static String userInput()
{
	try
	{
		BufferedReader br = new BufferedReader(
                                           new InputStreamReader(System.in));
		inputStr = br.readLine();
		
	}//end try
		
	catch (IOException ioe)
	{
		ioe.printStackTrace();
		System.exit(1);
	}//end catch
		
	return inputStr;
		
}//end method userInput

The drawMainMenu() method does no logic; it just displays the menu. It displays, however, the two choices the user can take: "1" to go to Transactions, and "2" to Exit. The String inputStr is declared globally as a static String.

There seems to be nothing wrong with userInput(), 'coz the userVerify() method also calls the same method and it works just fine. At the main method, however, if I enter "1" or "2" from userInput(), it still goes through the while loop! I can't understand what's wrong. Please help!

Thanks so much in advance for any advice/comment. All suggestions are very much appreciated.

[hardwired]

Use the equals method with Strings.

Code:

while (!inputStr.equals("1") && !inputStr.equals("2"))

[peachyco]

Whew! Thanks a lot for the quick help. I thought I had a problem with the logic and the calling of methods. I didn't realize it was just a simple issue with the While argument.

Thanks again a ton!