# does anyone know about the following error

• 03-11-2011, 11:36 AM
ajay.eeralla
does anyone know about the following error
Code:

```package funfun; import java.math.BigInteger; /** * * @author ajay */ public class Fun{ private final static BigInteger ONE=new BigInteger("1"); private final static BigInteger ZERO=new BigInteger("0"); private final static BigInteger TWO=new BigInteger("2"); public static BigInteger sqrt(BigInteger n) { BigInteger a = BigInteger.ONE; BigInteger b = new BigInteger(n.shiftRight(5).add(new BigInteger("8")).toString()); while (b.compareTo(a) >= 0) { BigInteger mid = new BigInteger(a.add(b).shiftRight(1).toString()); if (mid.multiply(mid).compareTo(n) > 0) { b = mid.subtract(ONE); } else { a = mid.add(ONE); } } return a.subtract(ONE); }//end of sqrt of n //legendre symbol public BigInteger legende(BigInteger n, int s) { BigInteger mone = new BigInteger("-1"); BigInteger p = new BigInteger("" + s); BigInteger d = p.subtract(ONE).divide(TWO); BigInteger c = n.modPow(d, p); if (c.compareTo(ONE) == 0) { return ONE; } else { return ZERO; } } /** * @param args the command line arguments */ public static void main(String[] args) { int fcount=8; int [] factorbase={2,3,11,17,19,23,43,47}; int k=0; BigInteger n= new BigInteger("1042387"); BigInteger Sqrt=sqrt(n); BigInteger t=Sqrt.add(ONE); int sscount=0; BigInteger [] s=new BigInteger[500]; BigInteger f; BigInteger m; while(t.compareTo(Sqrt.add(BigInteger.valueOf(41))!=0) { f=t.multiply(t).subtract(n).mod(n); for(int i=0;i<fcount;i++) { BigInteger z= BigInteger.valueOf(factorbase[i]); m=f.mod(z); if(m.compareTo(ZERO)==0) { s[k]=f; k++; sscount++; } } } for(int q=0;q<sscount;q++) { System.out.println(""+s[q]); } // if(jTextField2.getText().isEmpty()) // jTextField2.setText(jTextField2.getText()+s[q]); // else // jTextField2.setText(jTextField2.getText()+","+s[q]); } }```

run:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 500
at funfun.Fun.main(Fun.java:6
Java Result: 1
BUILD SUCCESSFUL (total time: 0 seconds)
• 03-11-2011, 12:10 PM
DarrylBurke