unreported exception java.io.IOException

[fluffaykitties]

So I'm trying to compile a program that calls the following function:

public void parseUrl(String source) throws IOException {
		
		...
		
		try {
			....
			}
		} 
		catch (MalformedURLException mue) {
			
			System.out.println("MalformedURLException occured");
			mue.printStackTrace();
			System.exit(1);
			
		} catch (IOException ioe) {
			
			System.out.println("IOException occured");
			ioe.printStackTrace();
			System.exit(1);
			
		}

There's more to this function, but this is where I'm getting the error, I believe.

This is the compile error:

unreported exception java.io.IOException; must be caught or declared to be thrown


Any ideas? I thought I formatted the try/catch correctly, but I guess not. I'm new to java, so any help would be appreciated.

Thanks!

[Junky]

The parseUrl method can throw an IOException. Where you call this method you need to handle the exception.

[fluffaykitties]

Don't I handle it here though with the catch part?

[fluffaykitties]

Or should I move the catch clauses to where I actually call the function, and throw the exception on that method?

[Junky]

Don't I handle it here though with the catch part?

Yes you do but the method signature says it will throw an IOException. All the compiler cares about is that where you call that method it MUST handle whatever exception is thrown (regardless if one gets thrown or not).

[Junky]

Or should I move the catch clauses to where I actually call the function, and throw the exception on that method?

Totally upto you.

[fluffaykitties]

Oh okay awesome. So all I did was add throws IOException to the method where I call the parseURL exception, and now it works. Thanks!

[Junky]

Well that is just hiding the problem. Now the method that calls the method that calls parseURL has to handle it. Does it makes sense to do that? Once again the design is upto you.

[fluffaykitties]

Yes, I think that's okay. Because the method that calls it is actually a constructor with just one line in it's body...the call to parseURL. So if parseURL throws the exception, the constructor just won't be created, and the program will exit.

Correct? (I may be wrong, and if so, please correct me!)

[fluffaykitties]

anyone? :confused::confused::confused:

[Junky]

What happened when you tried? Did it compile? Did it run?

[fluffaykitties]

I have other compile errors that I'm still working on, so I can't test it quite yet.