School Project - runing out of time D:

[Bagzli]

I need to take a string that has 3 words in it and split each word into a new string. New string will be an array. So for example I read a file and stored it in a two dimensional string array. then I take array[i][2] i being a number that will change since i'm doing this for each line and 2 is the part that contains the three words. Now i want to separate each word on its own and store it in a new two dimensional array but i just can't get it to work.

Here is sample code thats not working for me.

for(int i=0;i<3;i++)
		{
			initialArray[i][1].substring(0, initialCourses[i][1].indexOf(",")); //<----Line 19
			StringTokenizer str = new StringTokenizer(initialArray[i][2], " ");
			isolatedArray[i] = new String[str.countTokens()];
			int ctr = 0;
			while(str.hasMoreTokens())
			{
				String temp = str.nextToken().trim();
				System.out.println(temp);
				isolatedArrayi][ctr] = temp; 
				ctr++;
			}
		}

I have to use String Tokenizers. Where is my logic failing here?

Here is the error:

Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: -1
	at java.lang.String.substring(Unknown Source)
	at courseChanger.CourseChanger.main(CourseChanger.java:19)

I also should probably mention each line has a different number of words. and that the first part where i store the lines into a two D array works fine so you don't have to worry about any of that.

[KevinWorkman]

You want to split a String, eh? Why not use the split method then?

I'd help more, but I'm afraid that it would take too long and your time would run out by then.

[Shoss]

I agree with Kevin, but you might want to make sure initialArray[i][1] contains what you think. I assume you're getting the error because

initialCourses[i][1].indexOf(",")

didn't find a "," which would return -1.

Edit:
Also, line 19 seems unnecessary. The substring method returns a string which you're not storing anywhere.

[Bagzli]

Solution was:

Edit:
Also, line 19 seems unnecessary. The substring method returns a string which you're not storing anywhere.

Thank you