Regex help?

Well I'm writing this yet again because it signed me out when I went to post it, but anyhow, I am new to Java and am trying to use regex to extract an IP from a header but seems the more I read the more confused I'm getting. If someone could take a moment to post an example of how to extract a IP (127.0.0.1 for example) from a string and than print it so I could look it over and get a better understanding I would be very thankful. I've spent a fair amount of time reading various regex pages with no luck. I would really appreciate it. It's not the regex itself that confuses me it's actually implementing it to do this.

Let's see what you've tried so far, and please let us know how it doesn't work for you. Also, have you Googled "Java regular expression validating ip address"? Looks promising.

For example: validate ip address with regex

Quote:

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Originally Posted by Fubarable

Let's see what you've tried so far, and please let us know how it doesn't work for you. Also, have you Googled "Java regular expression validating ip address"? Looks promising.

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I've tried a bunch of different thigns, I have also checked those sites. I'm still confused on how to actually use the regex for this purpose. I don't see why it's so hard to just post an example of how to take the 127.0.0.1 out of a string like "Hey this is my 127.0.0.1", I've spent alot of time reading various sites and still am confused.

Also I checked out that site you posted last night, which just further confused me. I'm sure there's got to be a simpler example that doesn't have all kinds of extra code in it.

here's an example. note, this will not check whether your IP is really in a valid Class.

Code:

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public class RegexDemo2 {
    private static Pattern ex = Pattern.compile("\\d{1,3}\\.\\d{1,3}\\.\\d{1,3}\\.\\d{1,3}");
    private static Matcher match;
    public static void main(String[] args){
        String str = "this is my ip 127.0.0.1 the end. but here is another 10.10.1.0 ";
        match = ex.matcher(str);
        while (match.find() ){
            System.out.println( match.group() );
        }
    }
}

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first you have to define what the format for a correct IP address
for example 192.168.0.198, 198.234.89.0,.......

i don't know the rule regarding it but i think it consists of four parts separated by "." sign. if the numbers are of three digits then we can make regex as follows

"([\\d]){1,3}\\.([\\d]){1,3}\\.([\\d]){1,3}\\.([\\d]){1,3}"

i think you can change it as actual rule regarding IP address.

Quote:

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Originally Posted by JavaHater

here's an example. note, this will not check whether your IP is really in a valid Class.

Code:

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public class RegexDemo2 {
    private static Pattern ex = Pattern.compile("\\d{1,3}\\.\\d{1,3}\\.\\d{1,3}\\.\\d{1,3}");
    private static Matcher match;
    public static void main(String[] args){
        String str = "this is my ip 127.0.0.1 the end. but here is another 10.10.1.0 ";
        match = ex.matcher(str);
        while (match.find() ){
            System.out.println( match.group() );
        }
    }
}

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Brilliant! Thanks alot, really appreciate it. Clears that up.